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katovenus [111]
3 years ago
8

Vertex and name please​

Mathematics
1 answer:
DaniilM [7]3 years ago
5 0

Check the picture below.

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2 [30- (28-2)] +5<br> answer with explanation please!
Galina-37 [17]

Answer:

13

Step-by-step explanation:

Simplify the following:

2 (30 - (28 - 2)) + 5

Hint: | Subtract 2 from 28.

| 2 | 8

- | | 2

| 2 | 6:

2 (30 - 26) + 5

Hint: | Subtract 26 from 30.

| 2 | 10

| 3 | 0

- | 2 | 6

| 0 | 4:

2×4 + 5

Hint: | Multiply 2 and 4 together.

2×4 = 8:

8 + 5

Hint: | Evaluate 8 + 5.

8 + 5 = 13:

Answer:  13

6 0
3 years ago
Read 2 more answers
Use a graphing calculator and a system of
Gnom [1K]

Answer: -2 and 0

Step-by-step explanation:

3 0
3 years ago
Sam opened a money-market account that pays 3% simple interest. He started the account with $7,000 and made no further deposits.
jeka94
T = (1/0.03) [(8050/7000)-1]
t = 33.33 * 0.15
t= 5 yrs
5 0
3 years ago
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Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
PLEASE HELP , will reward brainliest
Bess [88]
The answer is 0 because If two events are mutually exclusive, then the probability of either occurring is the sum of the probabilities of each occurring.

Hope that Helps :)
5 0
3 years ago
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