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3 years ago

The area of a triangle can be found based on the area of a _____. circle trapozoid parallelogram

Mathematics

2 answers:

Sloan [31]3 years ago

7 0

Answer:

Trapezoid

Step-by-step explanation:

A triangle can be thought of as a trapezoid with one of the side length being 0.

antoniya [11.8K]3 years ago

6 0

Answer:

Parallelogram

Step-by-step explanation: "Surprisingly, this triangle (or any triangle) is related to a parallelogram." Found it in my text (Calvert Academy school)

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What is the slope of the line that passes through the points (-4, 0) and (-4, -10)? Write your answer in simplest form.

Tresset [83]

Answer:

<h2> There is no slope.</h2>

Step-by-step explanation:

$slope=\dfrac{y_2-y_1}{x_2-x_1}$

It means that for a line passing through two points to have the slope, the x-coordinates of these point have to be different.

(-4, 0) and (-4, -10) means x₁ = x₂ = -4, <u>so there is no slope.</u>

{the line is parallel to Y-axis, and has an equation: x=-4}

4 0

3 years ago

Convert 240 yards per hour (yd/h) to yards per minute (yd/min).

krek1111 [17]

9514 1404 393

Answer:

4 yd/min

Step-by-step explanation:

Change 1 hour to 60 minutes.

(240 yd)/(1 h) = (240 yd)/(60 min) = 4 yd/min

6 0

3 years ago

The domain and range

larisa86 [58]

Domain {3, 4, 0, 4, 3}
Range {-2, 4, -2, 1, 2}

hope it helps

5 0

3 years ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded by y=√x and y=x^2. Find V either by sl

Ede4ka [16]

Answer:

The volume of the solid is $3\pi/10$

Step-by-step explanation:

In this case, the washer method seems to be easier and thus, it is the one I will use.

Since the rotation is around the y-axis we need to change de dependency of our variables to have $f(x)\rightarrow f(y)$ . Thus, our functions with $y$ as independent variable are:

$x=\sqrt{y}\\ x=y^2$

For the washer method, we need to find the area function, which is given by:

$A=\pi\cdot [(\rm{outer\ radius)^2 -(\rm{inner\ radius)^2 ]$

By taking a look at the plot I attached, one can easily see that for a rotation around the y-axis the outer radius is given by the function $x=\sqrt{y}$ and the inner one by $x=y^2$ . Thus, the area function is:

$A(y)=\pi\cdot [(\sqrt{y} )^2-(y^2)^2]\\A(y)=\pi\cdot (y-y^4)$

Now we just need to integrate. The integration limits are easy to find by just solving the equation $\sqrt(y)=y^2$ , which has two solutions $y=0$ and $y=1$ . These are then, our integration limits.