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Hunter-Best [27]
4 years ago
5

Given f(x) = -2x - 1, solve for x when f(x) = -7

Mathematics
2 answers:
SOVA2 [1]4 years ago
7 0

Answer:

7 = -2x - 1

7 + 1 = - 2x

8 = - 2x

<u>8</u><u> </u> = x

2

4 = X

melomori [17]4 years ago
7 0
-2(-7) - 1
14-1

ANSWER: 13
You might be interested in
In a class of 50 students, 20 are taking french and 20 are taking german. of the students taking french or german, 10 are taking
EastWind [94]
Hello. Good?

Formula for calculating two overlapping sets:
A + B - both + not (A or B) = Total

20 (french) + 20 (german) - 10(both) + Not = 50
40 - 10 + not = 50
30 + not = 50 
not = 50 - 30 
not = 20


Answer: 20 students do not speak french or german. 

 Thanks, I hope I have helped.
8 0
4 years ago
Please help fast!!!!!!!
aivan3 [116]

Answer:

A

Step-by-step explanation:

because 1/9^2 is also 9^-2 because when it is a negative exponent it turns into a fraction. it does this because it is negative and the negative is equal to the number of one with the exponent positive

8 0
3 years ago
Factor.<br> 4z² – 8z - 5
Nataly [62]

Answer: z = -1/2 = -0.500

z = 5/2 = 2.500

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (22z2 -  8z) -  5  = 0  

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  4z2-8z-5  

The first term is,  4z2  its coefficient is  4 .

The middle term is,  -8z  its coefficient is  -8 .

The last term, "the constant", is  -5  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -5 = -20  

Step-2 : Find two factors of  -20  whose sum equals the coefficient of the middle term, which is   -8 .

     -20    +    1    =    -19  

     -10    +    2    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -10  and  2  

                    4z2 - 10z + 2z - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2z • (2z-5)

             Add up the last 2 terms, pulling out common factors :

                    1 • (2z-5)

Step-5 : Add up the four terms of step 4 :

                   (2z+1)  •  (2z-5)

            Which is the desired factorization

Equation at the end of step  2  :

 (2z - 5) • (2z + 1)  = 0  

Step  3  :

Theory - Roots of a product :

3.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

3.2      Solve  :    2z-5 = 0  

Add  5  to both sides of the equation :  

                     2z = 5

Divide both sides of the equation by 2:

                    z = 5/2 = 2.500

Solving a Single Variable Equation :

3.3      Solve  :    2z+1 = 0  

Subtract  1  from both sides of the equation :  

                     2z = -1

Divide both sides of the equation by 2:

                    z = -1/2 = -0.500

Supplement : Solving Quadratic Equation Directly

Solving    4z2-8z-5  = 0   directly  

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex :

4.1      Find the Vertex of   y = 4z2-8z-5

For any parabola,Az2+Bz+C,the  z -coordinate of the vertex is given by  -B/(2A) . In our case the  z  coordinate is   1.0000  

Plugging into the parabola formula   1.0000  for  z  we can calculate the  y -coordinate :  

 y = 4.0 * 1.00 * 1.00 - 8.0 * 1.00 - 5.0

or   y = -9.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = 4z2-8z-5

Axis of Symmetry (dashed)  {z}={ 1.00}  

Vertex at  {z,y} = { 1.00,-9.00}  

z -Intercepts (Roots) :

Root 1 at  {z,y} = {-0.50, 0.00}  

Root 2 at  {z,y} = { 2.50, 0.00}  

Solve Quadratic Equation by Completing The Square

4.2     Solving   4z2-8z-5 = 0 by Completing The Square .

Divide both sides of the equation by  4  to have 1 as the coefficient of the first term :

  z2-2z-(5/4) = 0

Add  5/4  to both side of the equation :

  z2-2z = 5/4

Now the clever bit: Take the coefficient of  z , which is  2 , divide by two, giving  1 , and finally square it giving  1  

Add  1  to both sides of the equation :

 On the right hand side we have :

  5/4  +  1    or,  (5/4)+(1/1)  

 The common denominator of the two fractions is  4   Adding  (5/4)+(4/4)  gives  9/4  

 So adding to both sides we finally get :

  z2-2z+1 = 9/4

Adding  1  has completed the left hand side into a perfect square :

  z2-2z+1  =

  (z-1) • (z-1)  =

 (z-1)2

Things which are equal to the same thing are also equal to one another. Since

  z2-2z+1 = 9/4 and

  z2-2z+1 = (z-1)2

then, according to the law of transitivity,

  (z-1)2 = 9/4

We'll refer to this Equation as  Eq. #4.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (z-1)2   is

  (z-1)2/2 =

 (z-1)1 =

  z-1

Now, applying the Square Root Principle to  Eq. #4.2.1  we get:

  z-1 = √ 9/4

Add  1  to both sides to obtain:

  z = 1 + √ 9/4

Since a square root has two values, one positive and the other negative

  z2 - 2z - (5/4) = 0

  has two solutions:

 z = 1 + √ 9/4

  or

 z = 1 - √ 9/4

Note that  √ 9/4 can be written as

 √ 9  / √ 4   which is 3 / 2

Solve Quadratic Equation using the Quadratic Formula

4.3     Solving    4z2-8z-5 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  z  , the solution for   Az2+Bz+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

           - B  ±  √ B2-4AC

 z =   ————————

                     2A

 In our case,  A   =     4

                     B   =    -8

                     C   =   -5

Accordingly,  B2  -  4AC   =

                    64 - (-80) =

                    144

Applying the quadratic formula :

              8 ± √ 144

  z  =    —————

                   8

Can  √ 144 be simplified ?

Yes!   The prime factorization of  144   is

  2•2•2•2•3•3  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 144   =  √ 2•2•2•2•3•3   =2•2•3•√ 1   =

               ±  12 • √ 1   =

               ±  12

So now we are looking at:

          z  =  ( 8 ± 12) / 8

Two real solutions:

z =(8+√144)/8=1+3/2= 2.500

or:

z =(8-√144)/8=1-3/2= -0.500

Two solutions were found :

z = -1/2 = -0.500

z = 5/2 = 2.500

3 0
3 years ago
Read 2 more answers
The path of a football can be modelled by the equation, h=-10d2+120d , where h represents the height, in metres, of the football
Marta_Voda [28]

Answer:

12 m

Step-by-step explanation:

The path of a football has been modeled by the equation:

h= -10d^2+120d

where h represents the height and d represents the horizontal distance.

When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.

=> 0= -10d^2+120d

=> 10d^2 - 120d = 0

d(10d - 120) = 0

∴ d = 0 m

and

10d - 120 = 0

=> d = 120 / 10 = 12 m

There are two solutions for d when h = 0 m.

The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.

The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m

3 0
4 years ago
In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W
lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= \frac{1}{2}

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the  top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted  incorrectly in incorrect order

in \sum_{k =2}^{5}(k - 1) = 10 ways  

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= \frac{6 \times 10}{120}

=\frac{1}{2}

 

8 0
3 years ago
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