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zhannawk [14.2K]
2 years ago
14

Fill in the missing values for the equation below

Mathematics
1 answer:
Firlakuza [10]2 years ago
8 0
Look where the line is touching on the y-axis and that will be your y-value. From there or somewhere on the line use rise over run (rise/run, do not divide). Count how many times it goes up and then count how many times it goes left or right. Make sure to look where the line is going, up or down slanted. If the line is going down, but slanted it will be a negative slope; line going up and slanted is positive.

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What is the horizontal shift for the graph of f(x) = (x - 3)3 + 2? A. Left 2 B. Right 2 C. Left 3 D. Right 3
jarptica [38.1K]
The graph of the function f(x) = (x - 3)^3 + 2 is 3 units to the right of the parent function.
Hence the horizontal shift is right 3.
3 0
2 years ago
If a heptagon has an area of 105 in2, what is the measure of one side ?
kumpel [21]

Answer:

5.38 inches

Step-by-step explanation:

The formula for Area of an Heptagon

= A=7/4a²cot(180°/7)

Area = 105in²

Side a = ?

The formula for Side a

= √4A ×tan (180°/7)/7

= √4 × 105 × tan (180°/7) /7

= 5.37536 inches

Approximately = 5.38 inches.

4 0
2 years ago
What is a measurement 90 degrees called
romanna [79]
It would be a right angle
4 0
2 years ago
Read 2 more answers
there are 110 apples in a basket on monday. on wednesday there is 80 apples left in the basket. what percent of apples are remai
vivado [14]

Answer:

the numbers of apples consumed is : 110 - 80 = 30.

percentage of apple consumed is : (30 / 100) * 100=27.27%

remaining numbers of apple =100 - 27.27 = 72.72%...

6 0
3 years ago
The sugar content of the syrup is canned peaches is normally distributed. Assumethe can is designed to have standard deviation 5
andreyandreev [35.5K]

Answer: 0.50477

Step-by-step explanation:

Given : The sugar content of the syrup is canned peaches is normally distributed.

We assume the can is designed to have standard deviation \sigma=5 milligrams.

The sampling distribution of the sample variance is chi-square distribution.

Also,The data yields a sample standard deviation of s=4.8 milligrams.

Sample size : n= 10

Test statistic for chi-square :\chi^2=\dfrac{s^2(n-1)}{\sigma^2}

i.e. \chi^2=\dfrac{(4.8)^2(10-1)}{(5)^2}=8.2944

Now, P-value = P(\chi^2>8.2944)=0.50477  [By using the chi-square distribution table for p-values.]

Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.50477

8 0
2 years ago
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