All categories

2 years ago

Write an equation for a line that passes through the Irgun and perpendicular to y=5x-2

Mathematics

1 answer:

umka21 [38]2 years ago

7 0

Answer:

Well we have to find eq of line passing through origin and perpendicular to y=5x-2

First you need slope

As slope of y=5x-2 line is 5

So, slope of perpendicular line is -1/5

Also it passes through origin

as we know eq of line is y-y1=m(x-x1)

substitute X1,y1 = (0,0)

it becomes y =mx

so, y = -x/5

5y +x = 0 is required equation

You might be interested in

what ordered pair is 2 spaces to the left and 4 spaces down from the point graphed on the coordinate plane?

kykrilka [37]

C. (-1, -2) would be your answer
That transformation is just a translation (x-2, y-4) from point (1,2)

8 0

3 years ago

A square and a rhombus have the following in common except

KATRIN_1 [288]

A square is a rhombus, but a rhombus is not always a square

3 0

2 years ago

The marginal profit in dollars on Brie cheese sold at a cheese store is given by Upper P prime (x )equals x (60 x squared plus 9

blondinia [14]

Answer:

Part A:

P(x)=15x^4+30x^3-50

Part B:

P(4)=$4270

Step-by-step explanation:

Part A:

In order to find the profit function P(x) we have to integrate the P'(x)

P'(x)=x(60x^2+90x)

P'(x)=60x^3+90x^2

$\int\limits {p'(x)} \, dx =\int\limits {60x^3+90x^2} \, dx$

P(x)=15x^4+30x^3+C

when x=0, C=-50

P(x)=15x^4+30x^3-50

Part B:

x=4

P(x)=15x^4+30x^3-50

P(4)=15*4^4+30*4^3-50

P(4)=$4270

Profit from selling 400 pounds is $4270

8 0

3 years ago

Automobile engineers wanted to check the effect of a new automatic transmission on mileage. They selected 50 cars of the same ma

daser333 [38]

Answer:

d. Twenty-five cars are randomly selected with the new transmission and 25 with the old transmission.

Step-by-step explanation:

A hypothesis test on the difference between the means must satisfy the following conditions

1) the samples must be randomly selected

2) each sample must have a known standard deviation

3) the samples must be independent

4) the samples must be from normal distribution

Hence only part d gives the right answer.

3 0

2 years ago

Use the formula to evaluate the series 1/4 + 1/9 + 1/27 + 1/81.

Dmitriy789 [7]

Is the first term supposed to be 1/4, or did you actually mean 1/3?

I'll assume the latter. Write

$S=\dfrac13+\dfrac19+\dfrac1{27}+\dfrac1{81}$
$S=\dfrac13+\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}$
$\dfrac13S=\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}+\dfrac1{3^5}$
$\implies S-\dfrac13S=\dfrac13-\dfrac1{3^5}$
$\dfrac23S=\dfrac13\left(1-\dfrac1{3^4}\right)$
$S=\dfrac12\left(1-\dfrac1{81}\right)$
$S=\dfrac{40}{81}$

8 0

2 years ago