Write an equation for a line that passes through the Irgun and perpendicular to y=5x-2
1 answer:
Answer:
Well we have to find eq of line passing through origin and perpendicular to y=5x-2
First you need slope
As slope of y=5x-2 line is 5
So, slope of perpendicular line is -1/5
Also it passes through origin
as we know eq of line is y-y1=m(x-x1)
substitute X1,y1 = (0,0)
it becomes y =mx
so, y = -x/5
5y +x = 0 is required equation
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