I think its C but I could be wrong.
I hope this helps :)
Answer:
part 1) 0.78 seconds
part 2) 1.74 seconds
Step-by-step explanation:
step 1
At about what time did the ball reach the maximum?
Let
h ----> the height of a ball in feet
t ---> the time in seconds
we have

This is a vertical parabola open downward (the leading coefficient is negative)
The vertex represent a maximum
so
The x-coordinate of the vertex represent the time when the ball reach the maximum
Find the vertex
Convert the equation in vertex form
Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point 
therefore
The time when the ball reach the maximum is 25/32 sec or 0.78 sec
step 2
At about what time did the ball reach the minimum?
we know that
The ball reach the minimum when the the ball reach the ground (h=0)
For h=0



square root both sides


the positive value is

Answer:
Step-by-step explanation:
t2/t1=r
-10/2=-5
2*-5=-10
Answer:
2x^3/x+5/x-5/ 3x-1
2x^3/ 3x-1
Step-by-step explanation:
we can cut plus and minus sign
7h - 2 = -51
7h = 2-51
7h = -49
h= -7