Regardless of the sign of
On the other hand,
which can never be negative for real
What value of c makes x^2+6+c a perfect square trinomial ?
2 answers:
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Regardless of the sign of
On the other hand,
which can never be negative for real
Answer:
s = - 1 ±
Step-by-step explanation:
Given
s² + 2s - 6 = 0 ( add 6 to both sides )
s² + 2s = 6
To complete the square
add ( half the coefficient of the s- term )² to both sides
s² + 2(1)s + 1 = 6 + 1
(s + 1)² = 7 ( take the square root of both sides )
s + 1 = ± ( subtract 1 from both sides )
s = - 1 ±
Thus
s = - 1 - , s = - 1 +
