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igor_vitrenko [27]
3 years ago
10

Margo’s dog, named Todd, weighed 120 pounds last year. She now weighs 180 pounds. What is the percent of change

Mathematics
2 answers:
alexira [117]3 years ago
5 0

Answer:

Step-by-step explanation:

\Delta \%=100\left(\frac{final-initial}{initial}\right)\\ \\ \Delta \%=100\left(\frac{180-120}{120}\right)\\ \\ \Delta \%=100\left(\frac{60}{120}\right)=50\%

elixir [45]3 years ago
3 0

Answer:

50%

Step-by-step explanation:

the increase is 60 so divide that by the original number; 60/120=0.5

now we have to change the decimal to a percent. multiply by 100 to do that and we get 50%.

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Answer:

2 visits

Step-by-step explanation:

Step one:

cost for membership=$27

cost per visit= $1

let the number of visit be x

the total is expressed as

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total =x+27

Step two:

given a total of $29

the number of visits can be found as

29=x+27

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3 years ago
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4 years ago
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4 years ago
Trigonometry, NEED HELP ASAP
Radda [10]

Answer:

sin(\theta_1) = \dfrac{\sqrt{357} }{29}

Step-by-step explanation:

The parameters of the angle θ₁ are;

The location of θ₁ = Quadrant II

cos(θ₁) = -22/29

We note the following;

1) The sine of an angle in quadrant II is positive

2) The cosine of an angle in quadrant II is negative,

2) The cos of an angle = The adjacent leg length to the reference angle divided by the hypotenuse length of a right triangle

3) With regards to the right triangle for finding cos(θ₁)

The adjacent leg length = -22 (The x-axis is negative in quadrant II)

The hypotenuse length = 29

The negative sign is obtained from the value of cosine in the quadrant

Therefore, by Pythagoras' theorem, for a right triangle, we have;

The opposite leg length to 'θ₁' = √(29² - 22²) = √(357)

sin\angle X = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

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sin(\theta_1) = \dfrac{\sqrt{357} }{29}.

5 0
3 years ago
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mote1985 [20]

Answer:

\large\boxed{f(x)=\dfrac{3}{2}x-1}

Step-by-step explanation:

\text{The slope-intercept formula:}\\\\y=mx+b\\\\m\ -\ slope\\b\ -\ y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{From the table we hve two points (0, -1) and (2, 2). Substitute:}\\\\m=\dfrac{2-(-1)}{2-0}=\dfrac{3}{2}

\text{Therefore the equation is}\ f(x)=\dfrac{3}{2}x-1\\\\\text{Check for  the point (4, 5):}\\\\f(4)=\dfrac{3}{2}(4)-1=(3)(2)-1=6-1=5\qquad\ CORRECT

7 0
3 years ago
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