<span>erry starts rowing at 2 pm from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 pm.
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Terry DATA:
rate = 60 meter/min ; time = x min ; distance = r*t = 60x meters
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Tao DATA:
rate = 40 meter/min ; time = x-5 min ; distance = r*t = 40(x-5) meters
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If they always row directly towards each other at what time will the two meet?
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Equation:
dist + dist = 2000 meters
60x + 40(x-5) = 2000
20x = 1800
x = 90 minutes
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0ne and one fifth or 1 and 1/5
Hello!
<h2>
31.3° and 58.7°</h2><h2>
</h2>
To solve, we can set up an algebraic expression.
Complementary angles add up to 90°, and in this instance, one angle is 27.4° more than the other. Therefore:
∠1 = x
∠2 = x + 27.4°
∠1 + ∠2 = 90°
x + (x + 27.4°) = 90°
Combine like terms:
2x + 27.4° = 90°
Subtract 27.4 from both sides:
2x = 62.6°
Divide both sides by 2:
x = 31.3°
Therefore, one of the angles is 31.3°. Solve for the measure of the other angle:
(31.3°) + 27.4° = 58.7°
Www.virtualnerd.com/algebra-2/quadratics/transforming-functions/vertex-form/convert-vertex-to-standa...
This will help you find what your looking for
