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kotegsom [21]
3 years ago
14

What is the missing number

Mathematics
1 answer:
Nana76 [90]3 years ago
5 0
The missing number is 81
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Express 194720 in standard form correct to 3 significant figures<br>​
ELEN [110]

Answer:

1.95 x 10^5

Step-by-step explanation:

First look at the 4th digit in the number 194720 as the the question said to round to 3 significant figures. If the 4th digit is more than 5, then add 1 to the third digit which results in 195000. Now the question also said to express in standard form. Look for the first non-digit number in 195000. After 1 put a decimal point and remove all the zeros after the point which results in 1.95. Now count how many digits you moved to the left which comes as 5. Write the answer as 1.95 x 10^5.

Hope you can understand this!!

3 0
2 years ago
GEOMETRY-TRIG
Andrej [43]

Answer:

6. The distance Rampy Ronald would have travelled horizontally is approximately 48.428 feet for an actual maximum height of 21.486 feet

7. Rampy Ronald is going to make the jump

Please find attached the graph of the motion of Rampy Ronald, created with Microsoft Excel

Step-by-step explanation:

6. The given parameters are;

The width of the ravine = 80 ft

The inclination of the ramp with which Rampy Ronald will jump = 30°

The distance from the edge of the ravine the ramp ends = 5 feet

The speed with which Rampy Ronald will make the jump = 60 mph

The maximum height he will reach = 30 feet

Therefore, we have;

The height of the end of the ramp = 15 × sin(30°) = 7.5

The height of the end of the ramp = 7.5 feet

The height of the jump = 30 - 7.5 = 22.5

The vertical velocity = 60 × sin(30°) = 30

The vertical velocity = 30 mph

The horizontal velocity = 60 × cos(30°) = 30·√3

The horizontal velocity = 30·√3 mph

From the kinematic equation, v² = u² - 2gh, we have;

u² = 2gh

h = u²/2g = 900/(2 × 32.17405) ≈ 13.986

The maximum height reached 13.986 + 7.5 = 21.486

From v = u - gt

t = u/g = 30/32.17405 ≈ 0.932

t  ≈ 0.932 s

The distance Rampy Ronald would have travelled horizontally = 30·√3 × 0.932 ≈ 48.428

The distance Rampy Ronald would have travelled horizontally ≈ 48.428 feet

7. The time before Rampy Ronald reaches ground level again, is given by the following relation;

h = 1/2·g·t²

21.846 = 1/2 × 32.17405 × t²

t = √(21.846/16.087025) ≈ 1.165

t ≈ 1.366 s

The horizontal distance traveled is therefore;

The horizontal distance traveled from maximum height is 30·√3 × 1.165 ≈ 60.535

The horizontal distance traveled from maximum height is ≈ 70.979 feet

The total horizontal distance traveled ≈ 48.428 + 60.535 = 108.963

The total horizontal distance traveled ≈ 108.963 feet

The total horizontal distance required to make it across the ravine = 5 feet + 80 feet = 85 feet

Therefore, Rampy Ronald is going to make the jump

8 0
2 years ago
HELP ME PLEASE!!! I’ll mark brainly
mixas84 [53]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP! PLEASE BE HONEST! ALGEBRA
ASHA 777 [7]

The answer is (2,-2)

5 0
3 years ago
20 POINTS AND BRAINLIEST !! PLEASE ANSWER THIS QUESTION !!
Elenna [48]
A
(X-7)(x-4) -> x^2 -11x + 28
Multiply that by the 2 and you get the original equation!
5 0
3 years ago
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