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Eduardwww [97]
3 years ago
11

Please help! Correct answer only, please! I need to finish this assignment this week. Determine the value of the following: A. B

. C. D.

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

Option B is correct

Step-by-step explanation:

To subtract matrix A from matrix B which has the same size as matrix A, you find the pair corresponding elements (which share the same position in matrix) and perform the subtraction.

As shown in picture:

C = A - B

   = [3-(-1)  2-0; -4-(-5)  6-2; 7-4  5-9]

   = [4 2; 1 4; 3 -4]

=> Option B is correct

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Here it is again. Please help me
igomit [66]

Answer:

First question: A, Second question: B

Step-by-step explanation:

0.5= 1/2

0.25= 1/4

0.4= 2/5

Now, insert these numbers, as fractions, back into the equation:

\frac{1}{4}- \frac{1}{2}+ \frac{1}{2}- \frac{1}{4}+ \frac{3}{5}+ \frac{2}{5}

Following PEMDAS you will get 1 as your answer.

7 0
3 years ago
Complete the factorization of 3x ^ 2 - 10x + 8 3x^ 2 -10x+8=(x- Box x-4)
aniked [119]

Answer:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

Step-by-step explanation:

The general form of a quadratic polynomial is given by:

ax^2+bx+c    (1)

You have the following polynomial:

3x^2-10x+8    (2)

In order to complete the factorization you can use the quadratic formula, to obtain the roost of the polynomial. The quadratic formula is given by:

x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}    (3)

By comparing the equation (1) with the equation (2) you obtain:

a = 3

b = -10

c = 8

Then, you replace these values in the equation (3):

x_{1,2}=\frac{-(-10)\pm \sqrt{(-10)^2-4(3)(8)}}{2(3)}\\\\x_{1,2}=\frac{10\pm2}{6}\\\\x_1=2\\\\x_2=\frac{4}{3}

Then, the factorization of the polynomial is:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

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Answer:

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4 years ago
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Svet_ta [14]
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8 0
3 years ago
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Scilla [17]

Answer:

Step-by-step explanation:

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3 years ago
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