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Eduardwww [97]
3 years ago
11

Please help! Correct answer only, please! I need to finish this assignment this week. Determine the value of the following: A. B

. C. D.

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

Option B is correct

Step-by-step explanation:

To subtract matrix A from matrix B which has the same size as matrix A, you find the pair corresponding elements (which share the same position in matrix) and perform the subtraction.

As shown in picture:

C = A - B

   = [3-(-1)  2-0; -4-(-5)  6-2; 7-4  5-9]

   = [4 2; 1 4; 3 -4]

=> Option B is correct

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Helga [31]

The sides of the triangle occur in a ratio of 4 : 7 : 2, so if <em>x</em> is some positive number, then we can write each side's length in terms of <em>x</em> as 4<em>x</em>, 7<em>x</em>, and 2<em>x</em>.

The perimeter is 299 yd, so

4<em>x</em> + 7<em>x</em> + 2<em>x</em> = 299 yd

13<em>x</em> = 299 yd

<em>x</em> = (299 yd) / 13

<em>x</em> = 23 yd

Then the sides of the triangle have lengths of

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7<em>x</em> = 7 • 23 yd = 161 yd

2<em>x</em> = 2 • 23 yd = 46 yd

"Median" here refers to the side length between the shortest and longest sides, so the answer would be 104 yd.

3 0
3 years ago
What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract
fgiga [73]

Answer:

|z| = 27 -- Modulus

\theta = \frac{\pi}{3} --- Argument

Step-by-step explanation:

Given

((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Required

Determine the modulus and the argument

We have that:

z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Expand:

z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

A complex equation can be expressed as:

z = |z| e^{i\theta}

Where

|z| = modulus

\theta = argument

Where

e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})

So:

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6 becomes

z = 27(e^{i\frac{\pi}{18}})^6

By comparison:

e^{i\theta} = (e^{i\frac{\pi}{18}})^6

This gives:

{i\theta} = i\frac{\pi}{18}}*6

{i\theta} = i\frac{6\pi}{18}}

{i\theta} = i\frac{\pi}{3}}

Divide through by i

\theta = \frac{\pi}{3}

Hence, the modulus, z is:

|z| = 27

And the argument \theta is

\theta = \frac{\pi}{3}

4 0
3 years ago
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nirvana33 [79]

Answer:

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Express the ratio in lowest form:<br>1.5 kg: 350 g​
irakobra [83]

Given:

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The lowest or simplest form of the given ratio.

Solution:

We know that,

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