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sesenic [268]
2 years ago
7

The CEO of Jisko requests our help in preparing year-end financial reports. The CEO explains that they are having difficulty cla

ssifying accounts. The Tableau dashboard shows December 31 year-end data from the company’s accounting system.
Prepare the current assets section of its December 31 year-end balance sheet.
Mathematics
1 answer:
AysviL [449]2 years ago
3 0

A current asset is an asset that can reasonably be expected to be sold, consumed, or exhausted through the normal operations of a business within the current fiscal year

<h3>What is current asset?</h3>

Your information is incomplete. Therefore, an overview of the current asset will be given. Current assets are those that you can convert into cash within one year, such as short-term investments and accounts receivable.

Current assets include cash, cash equivalents, accounts receivable, stock inventory, marketable securities, pre-paid liabilities, and other liquid assets.

Learn more about assets on:

brainly.com/question/25746199

#SPJ1

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alisha [4.7K]
Plug the x in :)

3(2) + 8
6 + 8
=14
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3 years ago
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While planning a hiking trip, you examine a map of the trail you are going on hike. The scale on the map shows that 2 inches rep
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Answer:

8.0

Step-by-step explanation:

eight inch big ooo thats the pick

7 0
3 years ago
Could someone please help me with this question? 15 points.
polet [3.4K]
1a) f(x) = I x+2 I. This is a piece-wise graph ( V form)
      x = 0 →f(x) =2 (intercept y-axis)
      x = -2→f(x) = 0 (intercept x-axis)
      x = -3→f(x) = 1 (don't forget this is in absolute numbers)
      x = -4→f(x) = 2 (don't forget this is in absolute numbers)
Now you can graph the V graph

1b) Translation: x to shift (-3) units and y remains the same, then
      f(x-3) = I x - 3 + 2 I = I x-1 I
     the V graph will shift one unit to the right, keeping the same y. Proof:
     f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
8 0
3 years ago
Prove that root 7 is irrational by the method of contradiction
Alchen [17]

Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

Therefore \sqrt7 is an irrational number.

8 0
3 years ago
(50 POINTS - WILL GIVE BRAINLIEST TO MOST HELPFUL ANSWER)
cricket20 [7]

Answer:

Part A:

x + y = 80

x + 20 = y

Part B:

Pam spends 30 minutes practicing math every day.

Part C:

It is not possible for Pam to have spent 60 minutes practicing dance because this means she must have practiced math for 40 minutes (60 - 20 = 40). This would total out to 100 minutes of total practice, not 80 minutes. Therefore, this is impossible.

Step-by-step explanation:

Part A:

"She spends 80 minutes every day practicing dance and math."

x + y = 80

"She dances for 20 minutes longer than she works on math."

x + 20 = y

Part B:

Solve for x:

x + 20 = y

Isolate variable x:

x = y - 20

Plug in this new value for the first equation:

y - 20 + y = 80

Combine like terms:

2y - 20 = 80

Isolate variable y:

2y = 100

y = 50

Plug in the new value of y into any equation:

x + 50 = 80

Isolate variable x:

x = 30

Part C:

x + 20 = y

x + 20 = 60

x = 40

x + y = 80

40 + 60 = 80

100 = 80

Impossible.

8 0
3 years ago
Read 2 more answers
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