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DIA [1.3K]
4 years ago
3

Which subtraction expression has the difference 1 + 4i? (–2 + 6i) – (1 – 2i) (–2 + 6i) – (–1 – 2i) (3 + 5i) – (2 – i) (3 + 5i) –

(2 + i)
Mathematics
2 answers:
gladu [14]4 years ago
4 0

Answer:

(3 + 5i) – (2 + i)

Step-by-step explanation:

(–2 + 6i) – (1 – 2i)

The real parts  -2-1 = -3

The imaginary parts 6i--2i = 6i+2i = 8i

(–2 + 6i) – (–1 – 2i)

The real parts -2 +1 = -1

The imaginary parts 6i --2i = 6i+2i =8i

(3 + 5i) – (2 – i)

The real parts 3-2 =1

The imaginary parts = 5i --i = 5i+i = 6i

(3 + 5i) – (2 + i)

The real parts 3-2 =1

The imaginary parts 5i -i = 4i

Marianna [84]4 years ago
4 0

Answer:

then the next question is going to be c

Step-by-step explanation:

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Solve the eqaution -12+5k=15-4k
Veronika [31]
Simple....

you have:

-12+5k=15-4k

isolate the variable...

-12+5k=15-4k
+12     +12

5k=27-4k

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Thus, your answer.
7 0
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nasty-shy [4]

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3 years ago
A given field mouse population satisfies the differential equation dp/dt=.4p-450 where p is the number of mice and t is the time
Flura [38]

Answer:

a) 7.78 months

b) 1116

Step-by-step explanation:

Given -

\frac{dP}{dt} = 0.4p-450

Integrating the above equation with respect to time, we get -

\int\ \frac{dP}{0.4p-450} = \int\ dt\\

let us define new variable x

x = 0.4p - 450 \\dx = 0.4 dy

substituting these values in above integral equation, we get -

\frac{1}{0.4} \int\ \frac{dx}{x} = \int\ dt\\ln x = 0.4 t + C\\x = ce^{0.4t}

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at t = 0, P (0) = 1075, using this condition, we get -

\frac{c}{0.4} = -50\\P(t) = 50 e^{0.4t} +1125 \\t = 7.78\\P(0) = 1125 - \frac{1125}{e^{4.8}} = 1116

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4 years ago
What is a way that you can write 83.041 in notation form?
Ann [662]
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