For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

$E = \frac{r}{p}$

In which r is the number of failures we want and p is the probability of a failure.

In this problem, we have that:

r = 1 because we want the first failed unit.

$p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5$

The expected number of systems inspected until the first failed unit is 2.5

8 0

3 years ago

Give the domain and range of each relationship. Determine whether or not each relationship is a function.

prisoha [69]

Answer:

Step-by-step explanation:

6 0

3 years ago

9(x) = 2x-1 r(x) = -2x 2 2 Find the value of r(q (2)).

BabaBlast [244]

Answer:

Answer is -6

Step-by-step explanation:

$given \: q(x) = 2x - 1 \\ and \: r(x) = - 2x \\ r(q(2)) = r(2(2) - 1) \\ \: \: = r(4 - 1) \\ = r(3) \\ = - 2(3) \\ = - 6 \\ therefore \: r(q(2)) = - 6$

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THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

6 0

3 years ago