Answer:
Option 3 or Option 4.
Step-by-step explanation:
I have this doubt because actually, a rhombus with a right angle (one) is not necessarily a square. Some rhombuses have one right angle and are still not squares. Now, if the four angles are right, it is a square, but this only says one.
On other hand, a parallelogram with congruent diagonals isn't a square necessarily either. Rectangles have congruent diagonals and are parallelograms.
In case you only can answer with one, I'll say is option 3, hope it helps!
Answer:
k = 30, 
Step-by-step explanation:
Since
is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

Then, replacing the derivatives in the equation we have:

Since
is a positive function, we have that
.
Now, consider a general solution
, then, by calculating the derivatives and replacing them in the equation, we get

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.
Therefore, the general solution is

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

Answer:
Step-by-step explanation: 800/x=100/17
(800/x)*x=(100/17)*x - we multiply both sides of the equation by x
800=5.88235294118*x - we divide both sides of the equation by (5.88235294118) to get x
800/5.88235294118=x
136=x
x=136
83% of 800=664
Answer:
Step-by-step explanation:
80, 82, 88, 90, 100
Now cross out the numbers starting with 80 and 100 and keep going till you get the middle number which would be 88