All categories

3 years ago

Write the standard form of the line that passes through the point (-2, 4) and is parallel to x - 2y = 6.

1 answer:

6 0

First calculate the function of x-2y=6:
x-2y=6 | - x
-2y=6-x | ÷ (-2)
y=0.5x-3

Now you have the function. Because the slope you search is parallel to this one, the slope is the same (in this case 0.5). A slope of 0.5 means for 2 steps to the right go one up. To define the function you are searching you have to find out the y intercept. For this take your point (-2|4). Now go as many steps to the right until you reach the y intercept or x=0 in this case you need 2 steps. So for 2 steps right you go one up. Now you have the y intercept (5).
The resulting function is: f(x) = 0.5+6.

You might be interested in

What is the slope of the line graphed on the coordinate plane

Mice21 [21]

Answer:

The slope = 3/4

Step-by-step explanation:

$m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

$m=\frac{6-3}{2-(-2)}=\frac{6-3}{2+2}$

m = 3/4

5 0

2 years ago

Read 2 more answers

The exponential function y= a(b)^x passes through the points (3,25) and (8,10). Which of the following is closest to the value o

Yuki888 [10]

If the exponential function $y=ab^x$ passes through the points (3,25) and (8,10), the value of b is 0.833

The given exponential equation is:

$y=ab^x$

The function passes through the points (3, 25) and (8, 10)

Substitute x = 3 and y = 25 into the function $y=ab^x$

$25=ab^3$ ............................(1)

Substitute x = 8 and y = 10 into the function $y=ab^x$

$10=ab^8$ .............................(2)

Divide equation (2) by equation (1)

$\frac{10}{25}=\frac{ab^8}{ab^3} \\\\0.4=b^5\\\\b=0.4^\frac{1}{5} \\\\b=0.4^{0.2}\\\\b=0.833$

Therefore, if the exponential function $y=ab^x$ passes through the points (3,25) and (8,10), the value of b is 0.833

Learn more on exponential functions here: brainly.com/question/12940982

6 0

2 years ago

What is the value of the expression |a + b| + |c| when a = –3, b = 7, and c = –15?

nikdorinn [45]

We know:
$|a|= \left\{\begin{array}{ccc}a&if\ a \ \textgreater \ 0\\0&if\ a=0\\-a&if\ a \ \textless \ 0\end{array}\right\\\\|2|=2\\|0|=0\\|-3|=3$

$|a+b|+|c|$
substitute a = -3; b = 7; c = -15
$|-3+7|+|-15|=|4|+15=4+15=19$

3 0

3 years ago

For what values of X are the statements below true

Galina-37 [17]

Answer:

See solutions below

Step-by-step explanation:

For what values of X are the statements below true

A. 1x>x+1

x >x+1

x-x>1

0x > 1

x > 1/0

X >∞

B) |1-x|>3

The fucntion can both be positive and negative

For the negative function

-(1-x) > 3

-1+x > 3

x > 3+1

x > 4

For the positive function

1-x > 3

-x > 3 - 1

-x > 2

x < -2

Hence the required solutions are x > 4 and x < -2

c) For the equation

|x-15| < 0

-(x - 15) < 0

-x + 15 < 0

-x < -15

x > 15

Also x-15 < 0

x < 0+15

x < 15

Hence the required solution is x > 15 and x < 15

3 0

3 years ago

Whats the answer and steps to 5g+4(-5+3g)=1-g

Lady_Fox [76]

$5g+4(-5+3g)=1-g \\\\ 5g-20+12g=1-g \\\\ 17g-20=1-g\\\\ 17g+g=1+20\\\\18g=21 \\\\ \boxed{g=\frac{21}{18}=\frac{7}{6}}$

4 0

3 years ago

Read 2 more answers