Question

Find the probability of 3 successes in 7 trials of a binomial experiment in which the probability of success in any one trial is 35%. Round to the nearest tenth of a percent.​

Answer 1

Answer: 0.07

Step-by-step explanation: Since it is a binomial experiment , we will use the formula:

n C r $p^{r}$$q^{n-r}$

p = 0.35

q = 1 - 0.35 = 0.65

n is the number of trials = 7

r = 3

substituting into the formula, we have

7 C 3 ($0.35^{3}$$0.65^{7}$

= 35($0.35^{3}$$0.65^{7}$

=0.0736

to the nearest tenth

= 0.07