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2 years ago

Does anyone understand this? show work please. thank you.

Mathematics

2 answers:

Lana71 [14]2 years ago

6 0

Answer:

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snow_tiger [21]2 years ago

3 0

Answer:

You need to satisfy the equation.

I will solve one.

Step-by-step explanation:

x -2 < -5

now add + 2 to both sides to keep its value.

now we end up with x <-3, which means that the value of x should be less than -3 in order to satisfy the equation.

So -5 is an answer, -4 is an answer, but not -3 because it should be less than -3 not equal.

As for number 9 the dash underneath the less than symbol means that it can equal to.

Hope this helps.

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Y equals the quotient of the quantity x squared plus 4 times x and the quantity x cubed minus 5.

koban [17]

Given:

Consider the completer question is "Find the derivative $\dfrac{dy}{dx}$ for $y=\dfrac{x^2-4x}{x^3-5}$ ."

To find:

The derivative $\dfrac{dy}{dx}$ .

Solution:

Chain rule: $\dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)$

Quotient rule: $\dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}$

We have,

$y=\dfrac{x^2-4x}{x^3-5}$

Differentiate with respect to x.

$\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)$

Using chain rule and quotient rule, we get

$\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}$

$\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}$

$\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}$

$\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}$

Therefore, the required answer is $\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}$ .

4 0

2 years ago

I NEED ANSWERS TO THESE QUESTIONS IT WAS DUE 5 mins ago and i have TILL 8:30 TO GET THEM DONE SOMEONE HELP A GIRL OUT

kondor19780726 [428]

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7 0

2 years ago

Compare the difference between an independent event and a dependent event.

pshichka [43]

<h2>⚠ANSWER⚠ </h2>

Dependent event is when two events are dependent events, one event influences the probability of another event whereas independent event has no effect on the probability of another event occurring.

↪DEPENDENT EVENT

When two events are dependent events, one event influences the probability of another event. A dependent event is an event that relies on another event to happen first. Dependent events in probability are no different from dependent events in real life. If you want to attend a concert, it might depend on whether you get overtime at work. if you want to visit family out of the country next month, it depends on whether or not you can get a passport in time. More formally, we say that when two events are dependent, the occurrence of one event influences the probability of another event.

Simple examples of dependent events

Robbing a bank and going to jail.
Not paying your power bill on time and having your power cut off.
Boarding a plane first and finding a good seat.
Parking illegally and getting a parking ticket.

↪INDEPENDENT EVENT

An independent event is an event that has no connection to another event’s chances of happening (or not happening). In other words, the event has no effect on the probability of another event occurring. Independent events in probability are no different from independent events in real life. Where you work has no effect on what color car you drive. Buying a lottery ticket has no effect on having a child with blue eyes.

When two events are independent, one event does not influence the probability of another event.

Simple examples of independent events

Owning a dog and growing your own herb garden.
Paying off your mortgage early and owning a Chevy Cavalier.
Winning the lottery and running out of milk.
Buying a lottery ticket and finding a penny on the floor.

☆...hope this helps...☆

3 0

2 years ago

Without calculating, explain how many decimal places are in the product 0.6 X0.4 X 1.9. Rewrite the expression as the product of

Vladimir79 [104]

There's only one decimal point in the answer. This is quite obvious. Regardless of whether or not your adding, subtracting, dividing, or multiplying, there's really only going to be one decimal, ever. This doesn't change, However, what DOES change are decimal PLACES.

Looking at the problem, you see both .6 and .4 are placed to the right of the decimal, otherwise known as the tenths place (1/10).

Looking at 1.9, you see you have one number (1) placed to the left of the decimal, the ones place, and another number placed to the right of the decimal (9), in the tenths place.

Well, this is simple. You can look and see that your multiplying fractions against a whole number, which will of course make this whole number even smaller. By how much though??

Well, you can really tell this by looking at how MANY numbers are behind the decimal. You have .9, .4, and .6

That's 3 numbers behind the decimal place. This may not help you solve the problem itself, but this tells you here (ignoring the 1, that will be taken out immediately while solving and turned into a 0) that you will have 3 numbers placed from the tenths place all the way to the thousandths place.

Basically, this tells you that you'll have three decimal places to the right of the decimal.

As for rewriting your problem to better show this, that's simple too.

All you have to do is simple multiplication, just in the tenths place. How? You know that 6*4 (referring to .6 and .4) is 24, that means that .6*.4 will be .24

How does this support your answer before? .24 has TWO numbers to the right of the decimal. That's TWO decimal places. With the .9 in 1.9, that's still THREE decimal places to the right of the decimal, and your answer would be the same.

So, here's it re-written.
1.9*.24=X

~Hope this helps!

4 0

3 years ago

Please help me with this question

Masja [62]

What is your question?

5 0

3 years ago