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Eddi Din [679]
3 years ago
9

Match each description with its symbolic representation. 1. P (A) The probability that both events A and B do not occur together

, but either may occur by itself 2. P (A ∩ B) The probability that event A occurs 3. P (A ∪ B) The probability that neither event A or event B occurs 4. 1 - P (A ∩ B) The probability that event A occurs given the fact that event B occurs 5. 1 - P (A ∪ B) The probability that either event A or event B occurs 6. P (A | B) The probability that both event A and event B occur

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Step-by-step explanation:

The answer is attached.

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Which state ment is true? 1) The y-intercept of Function A is greater than the y-intercept of Function B 2) the y-intercept of f
dolphi86 [110]

Answer:

I believe the answer is 1)

Step-by-step explanation:

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3 years ago
You want to buy some beans. An 8-ounce package costs $2.64. A 12-ounce package costs $3.84. A 26-ounce package costs $8.06. Whic
Daniel [21]

Answer:

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Step-by-step explanation:

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4 0
4 years ago
10<br> Find the slope of the line y = 5x + 4.<br> Slope
frez [133]

Answer:

The slope of the line is 5 because anything that has an x is the slope of the equation

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
4 years ago
The first side of a triangle is 4m shorter than the second side. The third side 3 times as long as the first side. The perimeter
viktelen [127]

Answer:

1st side= 4m

2nd side= 8m

3rd side= 12m

Step-by-step explanation:

Let the first, second and third side of the triangle be a, b and c meters respectively.

a= b -4 -----(1)

c= 3a -----(2)

Perimeter of triangle

= a +b +c

= 24

a +b +c= 24 -----(3)

From (1): b= a +4 -----(4)

Subst. (2) and (4) into (3):

a +(a +4) +3a= 24

3a +a +a +4= 24

5a +4= 24

5a= 24 -4

5a= 20

Divide both sides by 5:

a= 20 ÷5

a= 4

Substitute a= 4 into (4):

b= 4 +4

b= 8

Substitute a= 4 into (2):

c= 3(4)

c= 12

Thus, the lengths of the first, second, and third side of the triangle are 4m, 8m and 12m respectively.

4 0
3 years ago
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