
When you are asked what is the sin of π/6, or 30 degrees, you would look at the special triangle (30-60-90) to see that sin, or opposite over hypotenuse, of π/6 is 1/2. Arcsin, or csc, will present you with the ratio, 1/2, and ask for the angle. It's essentially working the question backwards.
Required probability is 0.8990
Given that,
p = 0.44
1 - p = 0.56
n = 736
0.01830
Converting Normal distribution to standard normal because A normal distribution is determined by two parameters the mean and the variance. A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution. Hence it's easy to work with standard normal distribution.
P(0.14<
<0.47) = P((0.41-0.44)/0.01830) <
<(0.47-0.44)/0.01830
Using normal algebra we get:
= P(-1.64 < z < 1.64)
= P(z < 1.64) - P(z < -1.64)
= 0.9495 - 0.0505
= 0.8990
Thus, required probability is 0.8990
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Answer:
The expenditure would be $ 8600
Step-by-step explanation:
If the cost is given by the function
C(x)= 10x + 6 where x is the number of days
The cost for 1 day would be
C(1)= 16 *100 = 1600 $ ( the expenses are in hundreds of dollars)
Then Putting x= 8 in the given equation we get
C(8)= 10(8) + 6
= 86
Multiplying 86 by 100 because expenditure rate per day is in hundreds of dollars
The expenditure would be $ 8600
Answer:
dA/dt= 12-2A(t)/900+t
Step by step Explanation:
Given:
rate of 3 gal/min
concentration of the solution entering is 4 lb/gal,
The equation of the solution can be expressed as
dA/dt = R(1)- R(2)
Where R(1)=( concentration of the salt at inflow* rate of input of given brine)
R(2)= ( concentration of the salt at inflow* rate of output of given brine)
R(1)= 3 gal/min× 4 lb/gal=12Ib/min
But the solution is been pumped slowly, the rate of the accumulation can calculated as;
(3 gal/min- 2 gal/min)=1gal/min
But after t min we will be having 900+t gallons present in the tank
CHECK THE ATTACHMENT FOR COMPLETE EXPLANATION