OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
At least 30 ..................
Answer:
6.5 x 10^-7
Step-by-step explanation:
Answer:
x is 3
and
y is 3
Step-by-step explanation:
(2*3)+(3*3) = 15
6+9 = 15
So since we know what x is, we can substitute it into the original equation for x like so to solve for y...
(2y - 8) + 5y - 10 = 0
2y - 8 + 5y = 10
2y + 5y = 18
7y = 18
y = 18/7 (or about 2.57)
So now we know what x is, we can sub it into the below equation to solve for x...
x = 2(18/7) - 8
x = 36/14 - 8 (or about -5.43)
