Which equation demonstrates the associative property of multiplication

Mathematics

1 answer:

kherson [118]3 years ago

3 0

Answer:

from what I remember ide say A

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How many pairs of parallel faces are shown? 3 5 4 6

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What is the common denominator? 3 4/9 and 2 5/6

Andrew [12]

18 is the common denominator

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3 years ago

What is the measure of angle VYZ

irakobra [83]

Answer:

$\boxed{\sf C. \ 161 ^{ \circ}}$

Step-by-step explanation:

Opposite angles are also congruent angles, meaning they are equal or have the same measurement.

$\sf \implies \angle VYZ = \angle WYT \\ \\ \sf \implies(8x + 1) ^{ \circ} = (9x - 19)^{ \circ} \\ \\ \sf \implies 8x^{ \circ} + 1^{ \circ} = 9x^{ \circ} - 19^{ \circ} \\ \\ \sf \implies 8x^{ \circ} - 9x^{ \circ} + 1^{ \circ} = - 19^{ \circ} \\ \\ \sf \implies - x^{ \circ} = - 19^{ \circ} - 1^{ \circ} \\ \\ \sf \implies \cancel{ -} x^{ \circ} = \cancel{- }20^{ \circ} \\ \\ \sf \implies x^{ \circ} = 20^{ \circ}$

$\therefore$

$\sf \implies \angle VYZ =(8x + 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =(8 \times 20 + 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =( 160+ 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =161 ^{ \circ}$

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3 years ago

Two roots of a 3-degree polynomial equation are 5 and -5. Which of the following cannot be the third root of the equation? 0 -5i

sammy [17]

Answer:

-5i and 5i cannot be roots of the equation, since they are complex.

Step-by-step explanation:

A 3-degree polynomial equation must have 3 roots, if one of its roots is a complex number, then its conjugate must also be a root of the function. The problem already stated two roots, which are reals, therefore the last root must also be real. Using this line of thought we know that -5i and 5i cannot be roots of the equation, since they're complex.

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