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3 years ago

Factorise the 2 questions above (c and f)

Mathematics

2 answers:

sveta [45]3 years ago

5 0

Answer:

Hi my lil bunny!

❀ _____.______❀_______._____ ❀

C) $5 ( x - 6) ( x - 4 )$ (Factor the polynomial.)

F) $2 ( x - 13) ( x + 10)$ (Factor the polynomial.)

Step-by-step explanation: (Factor the polynomial.)

❀ _____.______❀_______._____ ❀

Hope this helped you.

Could you maybe give brainliest..?

marin [14]3 years ago

4 0

Answer:

5x² - 50x + 120

Factor out the LCF which is 5

We have

5( x² - 10x + 24)

Write 10x as a difference

That's

5( x² - 6x - 4x + 24)

Simplify

Factor the expression

5 [ x ( x - 6) - 4( x - 6) ]

Factor out x - 4 from the expression

We have the final answer as

2x² - 6x - 260

Factor out 2 from the expression

That's

2 ( x² - 3x - 130)

Write 3x as a difference

That's

2 ( x² + 10x - 13x - 130)

Factorize the expression

2 [ x ( x + 10) - 13 ( x + 10) ]

Factor out x + 10 from the expression

We have the final answer as

Hope this helps you

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

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kondor19780726 [428]

Answer;

Step-by-step explanation:

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3 years ago

Please help! i just need the equations for the charts! grade 7 i give branliest<br>

True [87]

Answer:

Step-by-step explanation:

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3 years ago

The diameters of bolts produced in a machine shop are normally distributed with a mean of 6.46 millimeters and a standard deviat

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

Let X be the diameter of bolts produced in a machine shop

X is normal with mean = 6.46 mm and std dev = 0.05 mm.

We are to find the two diameters that separate the top 9% and the bottom 9%.

We can use std normal distribution value for this and from Z we can calculate X values

P(Z<z) = 0.09 and P(Z<z1) = 0.91

z=-1.341 and z1 = +1.341

Corresponding X values would be

for bottom 9%

X = 6.46-1.341*0.05 = 6.39295

X = 6.46+1.341*0.05=6.52305

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A construction company requires 25,400 bricks

maks197457 [2]

25,908 bricks must be ordered

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3 years ago