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artcher [175]
3 years ago
5

What is the slope, m, and the y-intercept of the line that is graphed below? On a coordinate plane, a line goes through points (

negative 3, 0) and (0, 3). m = 1; (0, 3) m = 1; (–3, 0) m = –1; (0, 3) m = –1; (–3, 0)

Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

m = 1; (0, 3) is the correct answer.

Step-by-step explanation:

The general equation of a line is given by:

y=mx+c

where, m is the slope of line

c is the y-intercept and

(x,y) are the points from where the line passes.

We are given that the line passes through 2 points (-3,0) and (0,3).

Putting the values of (x,y) in the equation of line.

Putting (0,3):

3 = m \times 0 + c\\\Rightarrow c =3

So, y-intercept is (0,3).

Hence, equation of line becomes:

y = mx + 3

Putting (-3,0) in y = mx + 3:

0 = m(-3) +3\\\Rightarrow 3m = 3\\\Rightarrow m =1

So, the equation of line becomes:

y = x +3

Please find attached graph.

m = 1; y intercept (0, 3) is the correct answer.

pochemuha3 years ago
3 0

Answer:

m = 1; (0, 3)

Step-by-step explanation:

took the test!!

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So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

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