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3 years ago

A circle with a radius of 10,20 or 4 inches has a central angle of 0.25 radians that intercepts an arc of 25,5 or 16 inches

Mathematics

1 answer:

WARRIOR [948]3 years ago

7 0

The radius would be 10 and the arc would be 5.
I hope this helps.
Have a blessed day!

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Emily is entering a bicycle race for charity. Her mother pledges $0.10 for every 0.25 mile she bikes. If Emily bikes 8 miles, ho

Arlecino [84]

Answer:

0.10 for 1/4 of a mile so 8 would be 32 times more. Which would be .1 x 32 or $3.20

Step-by-step explanation:

Plz mark brainliest :3

8 0

3 years ago

which answer choice explains the pattern for how to find the slope using an equation in standard form?

Liono4ka [1.6K]

Question is using standard formula ax+by=c to find the slope by converting into slope intercept form y=mx+b

so we also need to convert ax+by=c into y=mx+b as shown below:

$ax+by=c$

$ax+by-ax=c-ax$

$by=-ax+c$

divide both sides by

$y=-\frac{a}{b}x+\frac{c}{b}$

Now compare it with y=mx+b, we get

$m=-\frac{a}{b}$

So using values of a and b, we can find the slope

compare given equation -5x+2y=15 with ax+by=c, we get:

a=-5, b=2

Now plug both into above formula

$m=-\frac{a}{b}$

$m=-\frac{-5}{2}$

$m=\frac{5}{2}$

Now matching these details with given choices we find that THIRD choice is the final answer.

7 0

3 years ago

Pictures of the problem is attached! :)

hjlf

Answer:

Step-by-step explanation:

16 x 28% = 4.48

16 x 72% = 11.52

16 x 172% = 27.52

16 x 128% = 20.48

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I dont know for the second one, sorry-

8 0

3 years ago

The sum of two consecutive even numbers is 54. Find the numbers.

Reil [10]

Hi! the numbers are 26 and 28!

26+(26+2) =54

8 0

3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

5 0

3 years ago