Answer:
6.13
Step-by-step explanation:
Using Sine Law we know that

Using your figure let's assign sides and angles:
A=? B = 60° C = 70°
a = 5 b = ? c = x
If we put that into our formula:

Notice that we have too many unknowns. We need to complete at least one ratio to do this, so how do we do this?
Notice we have 2 angles given, so we solve for the third angle. The sum of all angles in any triangle is always 180°
∠A + ∠B + ∠C= 180°
∠A + 60° + 70° = 180°
∠A + 130° = 180°
∠A = 180° - 130°
∠A = 50°
Now we can use this to solve for x.

So the closest answer would be 6.13
Answer:
3rd answer down
Step-by-step explanation:
ok so you take the median of all the #'s which turns out to be 126.5 and that is where your bar should point to in the box, then you should start with 105, and your last bit of the line should end at 150, the start of your box should start at the median of 105 and 117, and the end of your box should stop at the median of 145 and 150.
Answer:
34
Step-by-step explanation:
Straight lines are 180 degrees, so the angle inside of the triangle next to the 127, is 53 degrees. (180-127= 53)
So to find "x", we need to figure out what the full number is.
59+53 = 112.
180-112= 68.
Now that we have the degree of the full angle, we can make an equation to find x.
x*2 = 68
(Divide 2 from both sides to isolate the variable)
x = 34
I hope this helped!
perpendicular lines have a slope that is a negative reciprocal
A) 4x-5y=5
subtract 4x
solve for y
-5y = -4x+5
divide by -5
y = 4/5 x+5 slope is 4/5 perpendicular slope is -5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = -5/4 (x-5)
B) 5x+4y = 37
subtract 5x
4y =-5x +37
divide by 4
y =-5/4 x +37/4 slope is -5/4 perpendicular slope is 4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = 4/5 (x-5)
C)4x+5y=5
subtract 4x
5y = -4x +5
divide by 5
y = -4/5 x +1
y =-4/5 x +1 slope is -4/5 perpendicular slope is 5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = 5/4 (x-5)
D)5x-4y=8
subtract 5x
-4y = -5x+8
divide by -4
y = 5/4 x-2
y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = -4/5 (x-5)