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vredina [299]
2 years ago
13

0.426 repeated as a fraction

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0
0.426 = 426/1000 = 213/500
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please help me with my sisters homework answers all of the questions please and show work I need it for today thanks
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What do I do, please help<br>or just tell me the answer ​
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You can use quizlet or maybe contact a friend
6 0
3 years ago
Multiple<br>1. Which of the following is Eular's formula?<br>OE-V + F = 2<br>OV-E+ F = 2​
Alinara [238K]

Answer:

see explanation

Step-by-step explanation:

Euler's formula for polyhedra is

V- E + F = 2

where V is number of vertices, E number of edges and F number of faces

6 0
3 years ago
0.9 (13) - 1.7 (3) =
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6.6

Step-by-step explanation:

8 0
2 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
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