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vredina [299]
3 years ago
13

0.426 repeated as a fraction

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0
0.426 = 426/1000 = 213/500
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Which of the following best defines amplitude?
DedPeter [7]
The true answer is 
<span>one-half the height between the crest and the trough (check your physics lesson)</span>
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4 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
Stanley measured a county park and made a scale drawing. The picnic area, which is 120
algol [13]

Answer:

3

Step-by-step explanation:

6 0
3 years ago
16
Bas_tet [7]

7.5cm

lets take point K represent lenght from M to perimeter of circle.

r is radius

KM= r-OM= r-4.5cm

now lets draw line from O to A (OA)

we get triangle.

hypotenuse is OA and it equals r(radius)

ab=12 cm. so another side of the triangle (AM) is 12/2=6cm. and the last side of the triangle is 4.5(OM)

use pythaghorean theorem

squares of sides added = square of hypotenuse

20.25+36=r^2(our hypotenuse is radius)

56.25=r^2

r=√56.25=7.5cm

5 0
3 years ago
Read 2 more answers
You are kayaking at a pace of 63 feet every 12 seconds. Your friend's pace is 21 feet every 2 seconds. Are you and your friend k
mamaluj [8]

Answer:

Your friend is kayaking faster.

Step-by-step explanation:

The way to approach this answer is by putting one of them in terms of the other. So that both are in terms of the same time. If you kayak 63 feet in 12 seconds how many feet do you kayak in 2 seconds? Simply divide by 6. 63/6 = 12/6. So, in 2 seconds (12/2) you kayak 10.5 feet (63/6). But your friend kayaks 21 feet in the same time... so he's going faster.

5 0
3 years ago
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