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nexus9112 [7]
3 years ago
7

What math worksheets are there?

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0
There are many online. You just have to search a specific one online and you can find many.
You might be interested in
6 times the sum of a number and 5 is 16
Ulleksa [173]
The equation would be 6 times x+5=16. This would be kinda Impossible. But a really close answer is 1.833
8 0
3 years ago
Approximate height of tower the person is
Slav-nsk [51]
Will you please provide more information and state a clear question
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Draw a diagram for this fraction<br><br>2 2/3​
LiRa [457]

Answer:

OOO

OOO

OO

Step-by-step explanation:

Where OOO is == 1.

OO is 2/3 of OOO.

7 0
3 years ago
junior rides his trucycle off a level porch. If he left the porch at a speed of 4 m/s and landed a horizontal distance of 2.5m f
WITCHER [35]

Answer:

the height of the porch is H=1.91 m

Step-by-step explanation:

neglecting friction and assuming that the porch is horizontal, then the horizontal speed is v₀= 4 m/s and it does not change , thus he hits the base at

t= L/v₀ , L= horizontal distance

then for vertical motion , since the vertical velocity vy is 0 , the initial height is H ( the height of the porche)  and the final height hf is 0 , we have

hf = H + vy*t - 1/2*g*t²

0 = H + 0 -1/2*g*t²

H = 1/2*g*t² = 1/2*g*(L/v₀)²

replacing values with g= gravity = 9.8 m/s²

H = 1/2*g*(L/v₀)² = 1/2*9.8 m/s² *( 2.5 m/ 4 m/s)² = 1.91 m

therefore the height of the porch is H=1.91 m

6 0
3 years ago
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