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Volgvan
3 years ago
11

The diagram shows a vertical tower DC on a horizontal ground ABC.

Mathematics
1 answer:
sasho [114]3 years ago
6 0
The measure of ABD=180°- 54°=26°
and then the measure of ADB= x
and x + 26° + 28°= 180°, sum of anlgle in a triagle property
 it means x= 180°- 26-28=126°
application of sinus law in the triangle

sin 28 / BD = sin 126/ AD = sin 26/ 25 so we can deduce that 

AD= 25sin126 / sin26= 46.12
let 's consider the triangle ADC, so for finding h, we have sin 28 = h / AD
and then h = AD x sin28=21.65

<span>Calculate the height of the tower is 21.65</span>

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Determine the type and number of solutions of −4x2 − 3x + 7 = 0.
Kaylis [27]

Answer:

Step-by-step explanation:

You have to use the discriminant for this. If the quadratic is -4x^2-3x+7, then

a = -4, b = -3, and c = 7. The formula for finding the discriminant is

D=b^2-4ac which comes from the quadratic formula, but without the square root sign. Filling in:

D=(-3)^2-4(-4)(7) which simplifies down to

D = 9 + 112 so

D = 121. This is a perfect square, so the solutions will be 2 real. Just so you know, you will NEVER have a solution like the one offered in the third choice down. If you have one imaginary root, you will ALWAYS have a second by the conjugate rule.

7 0
3 years ago
Word Problems : Subtract 18 rupees 9 paise from 75 rupees 80 paise<br><br>Write In Step by Step ​
AlladinOne [14]

Answer:

Question

Answers

Related Questions

Subtract the following:

A) 18 rupees 9 paise from 75 rupees 80 paise.

B) 49 rupees 79 paise from 123 rupees 68 paise.

Answer

VerifiedVerified

139.5k+ views

17.4k+ likes

Hint: Use decimal concept.

We know that, 1 rupee = 100 paise. We can reframe these questions as follows:

18 rupees 9 paise from 75 rupees 80 paise

18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,

75.80−18.09−−−−−− 57.71

Which means 57 rupees 71 paise

49 rupees 79 paise from 123 rupees 68 paise

49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,

123.68 −49.79−−−−−− 73.89

Which means 73 rupees 89 paise.

Note: We can also perform the subtraction by making all units the same that are paise and then subtract.

5 0
3 years ago
Read 2 more answers
Write a word problem involving fractions for which you would use the work backward strategy and addition to solve. Include solut
Delicious77 [7]
Mrs. Annie went to a store, spent half of her money and then $10 more. She went to a second store, spent half of her remaining money and then $10 more. But she then had no money left. How much money did she have to begin with when she went to the first store?
Answer: $60
7 0
3 years ago
A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is
scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

\bar X_{1}=360000 represent the mean for the downtown restaurant

\bar X_{2}=340000 represent the mean for the freeway restaurant

s_{1}=50000 represent the sample standard deviation for downtown

s_{2}=40000 represent the sample standard deviation for the freeway

n_{1}=36 sample size for the downtown restaurant

n_{2}=36 sample size for the freeway restaurant

t would represent the statistic (variable of interest)

\alpha=0.05 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis:\mu_{1}\leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level\alpha=0.05 and \alpha/2=0.025 we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is t_{1-\alpha/2}=1.66

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

p_v =P(t_{70}>1.874)=0.033

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0
3 years ago
1/3 of a number is 12 less than the number itself
natulia [17]
Let "x" be a substitute for "a number"

1/3(x)=x-12    Multiply by 3
x=3x-36         Get n onto the same side of the equation
2x=36            Divide by 2
x=18

That's your answer.
5 0
3 years ago
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