All categories

4 years ago

How do I determine 8^402 mod 5?

1 answer:

8 0

It would be a great idea to narrowing it down to (2^3)^134 mod 5. now it is easier cause 8 = 3 (mod 5), let's compute 3^402 (mod 5).
3^4 = 81 = 1 (mod 5). 
Therefore, 3^402 = (3^4)^100 * 2^2 = 1^100 * 4 = 4 (mod 5).

You might be interested in

Write the Slope- Intercept equation of the line that passes through the given point and is perpendicular to the given line (0, -

damaskus [11]

Answer:

y+4=-3(x+0) or y=-3x-4

Step-by-step explanation:

so you have to make it in form y=mx+b

that would be y=1/3x-2/3

for a perpendicular line, you would need to find the opposite reciprocal of the slope

3/1 or 3 would be the reciprocal, so to make it opposite would be -3

So it would be y-y1 = m(x-x2)

fill it in with the coordinates (0,-4)

y+4=-3(x-0)

to get it to slope intercept form you have to simplify, and after that you get y=-3x-4

4 0

3 years ago

Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

3 years ago

4x-y=2 what is the solution

Rudiy27

Answer= y=-_

Step-by-step explanation:

y= -2+4x

4 0

3 years ago

plot the reflection of point A across the x-axis. what are the coordinates of the reflection of point A across the x-axis? what

dsp73

You reflect point A over the x-axis, double the distance from point a to the x-axis, then give the coordinates.

ex/ point A to the x-axis: 6, reflection: 12. coordinates (-6, 5)

8 0

3 years ago

Name the property of multiplication illustrated 112 X 1 = 112

Nat2105 [25]

Answer:

Identity property

Step-by-step explanation: because the product of any number and one is that number

4 0

3 years ago