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3 years ago

If (x-2) squared =49, then x could be?

2 answers:

7 0

Solve for x

(x-2)^2=49
Square root both sides
x-2=7
Add 2 to both sides
Final Answer: x=9

Make sure 9 is the correct answer

(9-2)^2=49
Subtract 2 from 9
7^2=49
Square 7
Final Answer: 49=49

This proves that 9=x

yulyashka [42]3 years ago

3 0

(X-2)^2=49
(9-2)^2=49
7^2=49
49=49
X = 9

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3 years ago

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4 years ago

A young couple purchases their first new home in 2011 for $95,000. They sell it to move into a bigger home in 2018 for $105,00

mart [117]

Given:

The value of home in 2011 is $95,000.

The value of home in 2018 is $105,000.

To find:

The exponential model for the value of the home.

Solution:

The general exponential model is

$y=ab^x$ ...(i)

where, a is initial value and b is growth factor.

Let 2011 is initial year and x be the number of years after 2011.

So, initial value of home is 95,000, i.e., a=95,000.

Put a=95000 in (i).

$y=95000b^x$ ...(ii)

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$105000=95000b^7$

$\dfrac{105000}{95000}=b^7$

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Taking 7th root on both sides, we get

$\left(\dfrac{21}{19}\right)^{\frac{1}{7}}=b$

Put $b=\left(\dfrac{21}{19}\right)^{\frac{1}{7}}$ in (ii).

$y=95000\left(\left(\dfrac{21}{19}\right)^{\frac{1}{7}}\right)^x$

$y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$

Therefore, the required exponential model for the value of home is $y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$ , where x is the number of years after 2011.

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3 years ago