Answer:
Probability that detector B goes off is '0.615'
Step-by-step explanation:
Given that:
1) Probability that detector A goes off and detector B does not go off is 0.25.
2)Probability that detector A does not go off is 0.35.
3)Probability that detector A goes off is (1-0.35)=0.65
Assuming that
Probability that detector B goes off is 'p' Hence the probability that detector B does not goes off is (1-p)
Thus the probability that detector A goes off and detector B does not go off is product of the individual probabilities
Probability that detector B goes off is '0.615'
2/3x + 4 = 7
-4 -4
4 cancels out.
2/3x = 3
x 3 x3
6/3 = 2x = 9
/2 /2
2 cancels out.
x = 9/2 = 4.5
6+2/3% <--- Given
(6+2/3)/100 <--- Definition of percent
(20/3)/100 <--- Putting the top into an improper fraction
20/300 <--- Dividing the fractions
1/15 <--- Simplifying the fraction
Hope this helps!
The discount price is .80x or 1-.20x.