The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.
|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees
= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)
= 593 in^2 + 126 in ^2 approximately
= 719 in^2 approximately
Then the length of side AC is approx. √(716 in^2) = 27 in
Answer: The weight of the iceberg at the end of the day will be 449,100 lbs.
Step-by-step explanation: The question is solved by first calculating what the loss of weight is during the day. The question indicates that it will lose .2%. In order to calculate the loss you need to multiply 450,000 x .002, which equals 900. Next, we subtract the weight loss from the original weight to determine the end of day weight. 450,000 - 900 = 449,100 lbs.
It's the first one (12, 15, 15, 17, 19, 19, 20, 22, 24)
10-3 or 10+(-3) that should help
