Answer:
0.862 liters of a 0.20 M NaCl solution (aq) contains 10.0g of NaCl.
Explanation:
In a mixture, the chemical present in greater quantity is called solvent, while the other components are called solutes. One way to quantify the amount of solute in a solution is by molarity or molar concentration, which is number of moles of solute that are dissolved in a given volume. Molarity can be calculated using the following equation:
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Molarity is expressed in units (moles / liter).
In this case,<em> 0.20M NaCl (aq) indicates that in 1 liter of solution, 0.20 moles of NaCl is present.</em>
But you want to know the amount of solution volume that contains 10.0g of NaCl.
So, knowing that the molar mass of NaCl is 58 g / mol, you must first know the amount of mass in grams that contains 0.20 moles of the compound. This can be calculated using a rule of three.
The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. Remember that proportionality is a constant relationship or ratio between different magnitudes.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other ( or when one magnitude decreases, so does the other), the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:
a ⇒ b
c ⇒ x
Then
In this case the rule of three is applied as follows: if 58 grams of NaCl are contained in 1 mole of the compound, how many grams does 0.20 moles of NaCl contain?
<em>grams= 11.6 </em>
Since 0.20 moles contain 11.6 grams of NaCl and remembering the definition of molarity, it is possible to say that <em>in a liter of solution there are 11.6 grams of NaCl solute.</em>
To calculate the amount of solution volume containing 10.0 g of NaCl, a rule of three is reapplied as follows: if 1 liter of solution contains 11.6 grams of NaCl, how many liters of solution contain 10 grams of NaCl?
<u><em>liters of solution=0.862</em></u>
This means that <u><em>0.862 liters of a 0.20 M NaCl solution (aq) contains 10.0g of NaCl.</em></u>