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3 years ago

Can someone plz help plz show work

Mathematics

1 answer:

aliya0001 [1]3 years ago

8 0

Answer:

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

$h^2=4^2+3^2\\\\h^2=16+9\\\\h^=25\to h=\sqrt{25}\\\\h=5\ ft$

The Lateral Area is the sum of the areas of three rectangles:

$4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2$

The Lateral Area:

$LA=A_1+A_2+A_3\to LA=8+6+10=24\ ft^2$

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1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago

Some number was divided into 104.13. This quotient was multiplied by 4, after which the resulting product was added to 5. Given

SVEN [57.7K]

Answer:

The initial number is <u>-1218.321</u>.

Step-by-step explanation:

Let the initial number be 'x'.

The number 'x' is divided into 104.13.

So, we divide the number 'x' by 104.13. This gives,

$\dfrac{x}{104.13}$

Now, the quotient is multiplied by 4. So, this means we need to multiply 4 to the fraction above. This gives,

$\dfrac{x}{104.13}\times 4\\\\\frac{4x}{104.13}$

Now, 5 is added to the result. This gives,

$\frac{4x}{104.13}+5$

Now, as per question:

$\frac{4x}{104.13}+5=-41.8$

Now, solving for 'x', we add -5 both sides. This gives,

$\frac{4x}{104.13}+5-5=-41.8-5\\\\\frac{4x}{104.13}=-46.8\\\\4x=-46.8\times 104.13\\\\4x=-4873.284\\\\x=\frac{-4873.284}{4}=-1218.321$

Therefore, the initial number is -1218.321.

6 0

3 years ago

How to find X in a parallelogram

myrzilka [38]

Answer:

X=7

Step-by-step explanation:

15-8

4 0

3 years ago

Find the value of x and then find m∠H. PLEASE HELP

kramer

Answer:

Here,

6x - 1 + 5x + 17 = 126

or,11x + 16 =126

or, 11x = 110

Therefore,x=10

the value of angle h is=6x-1

=6×10-1

=59#

5 0

3 years ago

One cell phone company offers a plan that costs $23.99 and includes unlimited night and weekend

MrMuchimi

Answer: 18 minutes

Step-by-step explanation:

Plan one: 23.99

Plan two: 17.99+(0.35x). X equals charge per minute at night and weekends.

We can subtract our main payment plans that don’t include variables, 23.99-17.99=6. We can then divide by our constant... 6/0.35 to get 17.14... minutes. so we can round up to 18 mins.

To make sure we are correct we can do,

17.99+(0.35)(18) to get 24.29 which is greater than 23.99.

MARK ME AS BRAINLIEST PLEASE!!!

6 0

3 years ago