1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arte-miy333 [17]
3 years ago
15

Given a right triangle with a hypotenuse of 15 feet and a height of 6 feet, find the measurement of angle

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:

66.42° between height and hypotenuse

23.58° between base and hypotenuse

Step-by-step explanation:

Using the concept of cosine and sine, we know that cosine of an angle is equal to the adjacent divided by hypotenuse.

Similarly, sine of an angle is given by opposite divided by hypotenuse

Tangent is given by opposite divided by adjacent

In rhis case, we use cosine

\theta=cos^{-1}(\frac {6}{15})=66.4218215217982\\\theta\approx 66.42^{\circ}

Therefore, the angle between the hypotenuse and height is 66.42°

To find the angle between base and hypotenuse, since it is a right angle triangle then the other angle will be 90-66.42=23.58°

You might be interested in
5√-54 in simplest radical form
rjkz [21]

YOUR ANSWER IS 15i radical 6


7 0
3 years ago
water stations will be placed every 600 meters of a fifteen kilometer race. how many water stations will be needed?
Snezhnost [94]
1km=1000metres
15km=15000 metres 
15000/600=25
25-1=24 (minus the last one)

hope this helps :)
5 0
3 years ago
Read 2 more answers
How many solutions are there in the given equation?<br> y = 2x² + 6x + 4
tigry1 [53]

Step-by-step explanation:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

2

+

6

+

4

=

0

2x^{2}+6x+4=0

2x2+6x+4=0

=

2

a={\color{#c92786}{2}}

a=2

=

6

b={\color{#e8710a}{6}}

b=6

=

4

c={\color{#129eaf}{4}}

c=4

=

−

6

±

6

2

−

4

⋅

2

⋅

4

√

2

⋅

2

x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{2}}}

x=2⋅2−6±62−4⋅2⋅4

brainliest and follow and thanks

8 0
3 years ago
How do we do with this formula? Help me with A pls​
Ugo [173]

Gradient is the slope, which is the letter m in the equation.

The point is written as (x1, y1) so replace x1 and y1 in the equation with the numbers in the given point.

A would be y - 1= 2(x-4)

B: y +5 = 5(x-2)

C: y-1= -3(x+1)

D: y -6 = 1/2(x-1)

E: y +1/4 = -2(x-3:4)

F: y+7 = -1/5(x+ 3)

3 0
3 years ago
Read 2 more answers
Question 7 of 10<br> What is the length of BC in the right triangle below?
horsena [70]

Answer:

A

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

BC² = 9² + 12² = 81 + 144 = 225 ( take the square root of both sides )

BC = \sqrt{225} = 15 → A

7 0
2 years ago
Read 2 more answers
Other questions:
  • Solve. G + 1/11 = 2/4<br> G = 1/44<br> G = 9/22<br> G = 13/22<br> G = 1/15
    8·1 answer
  • How do you solve the problem?
    10·1 answer
  • 0.0090 in scientific notation
    15·1 answer
  • What time is 17 hours after 1:00 p.m?
    15·2 answers
  • Ilene is playing in a basketball tournament and scored 24 points in her first game. If she averages over 20 points for both game
    7·1 answer
  • I need the written form for 293,805
    13·1 answer
  • Combine like terms, need help ASAP
    7·1 answer
  • Gracie owns a deferred annuity. The contract is tied to a market index, which was at 1000 when Gracie purchased the product and
    14·1 answer
  • What is equivalent to the following expression select all that apply.
    14·2 answers
  • Write a real-WORD problem that corresponds to the equation
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!