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Harman [31]
3 years ago
13

A 200-g hockey puck is launched at an initial speed of 16 m/s up a metal ramp that is inclined at a 30° angle. The coefficients

of static and kinetic friction between the hockey puck and the metal ramp are µs = 0.40 and µk = 0.30, respectively. What vertical height does the puck reach above its starting point
Computers and Technology
1 answer:
rusak2 [61]3 years ago
8 0

Answer:

h = 8.588 m

Explanation:

Given:

Mass of hockey puck:  m  =  200  g  =  0.2  K g

Angle of incline:  θ  =  30º   (with respect to horizontal)

Coefficient of static and kinetic friction between the puck and ramp:  

μ s  =  0.4   and    μk  =  0.3

initial speed:  

v  =  3.5  m /s

Let  h  be the vertical height reached by the puck, above the ground. This corresponds to a distance of  

d =  h *sin  30º =  2 *h

along the incline. As the puck is moving, only kinetic friction comes into play as it climbs up the incline. Let  N  be the normal reaction exerted by the metal ramp on the ball. Then,

N  =  m*g *cos  θ  =  0.2 *9.8 1*cos  30 º =  1.6991  N

Therefore, kinetic friction acting on the puck is:  

F k  =  μ k *N  =  0.3 *1.6974  =  0.50974 N

From work energy theorem, the change in kinetic energy should equal the work done by friction and gravity. Therefore,

0.5*  0.2 *16²  =  0.50974 *2h + 0.2*9.81*h

⇒  h = 8.588 m

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koban [17]

Answer:

<em>The program written in Python is as follows:</em>

def solution(N):

     concat = ""

     for i in range(1,N+1):

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

           else:

                 if i%2 == 0:

                       concat= concat+"Codility"

                 if i%3 == 0:

                       concat= concat+"Testers"

                 if i%5 == 0:

                       concat= concat+"Coders"

                 print(concat)

                 concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

     concat = ""

This line iterates from 1 to the input integer

     for i in range(1,N+1):

<em>This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed</em>

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

<em>If otherwise</em>

           else:

<em>This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat</em>

                 if i%2 == 0:

                       concat= concat+"Codility"

<em>This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat</em>

<em>                 </em> if i%3 == 0:

                       concat= concat+"Testers"

<em>This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat</em>

                 if i%5 == 0:

                       concat= concat+"Coders"

<em>The concatenated string is printed using this line</em>

                 print(concat)

This variable concat is intialized back to an empty string

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The main method starts here

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6 0
3 years ago
Explain how you would insert graphics using your word-processing software.
scoundrel [369]
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5 0
3 years ago
Your program is going to compare the scores of two volleyball teams that play each other. To win a match in volleyball, a team m
Alenkasestr [34]

Answer:

#section 1

team1=0

team2=0

matches=[1,2,3,4,5]

for i in matches:

   print("For Game ", i)

#section 2

   while True:

       try:

           scoreA = int(input("Enter score for first team: "))

           scoreB = int(input("Enter score for second team: "))

       

           if scoreA < 25 and scoreB < 25:

               raise ValueError

           try:

               if abs(scoreA - scoreB) < 2:

                   raise  

               else:

                   break

           except:

               print("difference less than 2")

   

       except ValueError:

           print("Enter correct scores")

#section 3

       print("For Game ", i)

   if scoreA > scoreB:

       team1 = team1 + 1

   else:

       team2 = team2 + 1

#section 4

if team2 > team1:

   print("Team 2 is the winner")

else:

   print("Team 1 is the winner")

Explanation:

There is no way you can run the code without using a break statement because, in a while loop you have to pass an argument that will exit the loop. if you don't your loop will keep running and that's not good.

You might have also gone about it in a way that is a bit complicated. when writing code always look out for ways to make your work easier.

I used a For Loop, While Loop and an array.

#section 1

team1=0  

team2=0  

matches=[1,2,3,4,5]  

for i in matches:  

print("For Game ", i)  

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- An Array holding the number of games they're to play was also declared. they are playing 5 so the Array "matches" holds 5 elements.

- The first loop here is the "For loop" and what it does is to run the block of code under it for all the elements in the Array.

- finally we print for game "i" where i is each game in the array

#section 2

 while True:

       try:

           scoreA = int(input("Enter score for first team: "))

           scoreB = int(input("Enter score for second team: "))

       

           if scoreA < 25 and scoreB < 25:

               raise ValueError

           try:

               if abs(scoreA - scoreB) < 2:

                   raise  

               else:

                   break

           except:

               print("difference less than 2")

   

       except ValueError:

           print("Enter correct scores")

- A while loop is always true unless it encounters an argument that is not true or a break statement is inserted.

- This section is responsible for taking all the inputs required and if a wrong input is entered it would show the specific error and ask you to make the input again.

- Here the Try and Except is use to handle the errors. When the Try block encounters an error it goes to the Except block and executes whatever it finds there.

- The first try block prompts and takes inputs, it then checks if the values inputted satisfies or violates the 25-point rule.

If it does not satisfy the 25-point rule, it goes to it's error block and prints "enter correct score" and the WHILE loop runs again.

within this Try block is nested another try block. if the first try block does not raise any error it proceeds to the second try block.

- The second Try block checks the difference between the scores and if it is less than 2, it raises an error and prints difference is less than 2 and runs the WHILE loop again.

- If there are no errors it BREAKS out of the WHILE loop then the FOR loop moves to the next match.

#section 3

       print("For Game ", i)

   if scoreA > scoreB:

       team1 = team1 + 1

   else:

       team2 = team2 + 1

- Remember there is still a for loop. This section prints the game we just recorded, and checks which team won. It then adds the win as a point(1) to the teams total score.

#section 4

if team2 > team1:

   print("Team 2 is the winner")

else:

   print("Team 1 is the winner")

- In this section the For Loop has finished running and the final values are ready, it compares the scores of both teams and declares the winner.

I have placed an attachment to help you see the code in action.

5 0
3 years ago
PLEASE ANSWER THIS ASAP‼️
Reil [10]

c) the grasses

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4 0
3 years ago
Read 2 more answers
the first day anna read a quarter of the book. on the second day she read a third of the remainder. noticed that after two days
Misha Larkins [42]

Answer:

160 pages

Explanation:

Day\ 1 = \frac{1}{4}

Day\ 2 = \frac{1}{3}Remainder

Left = 80

Required

The number of pages

Let the number of pages be x.

So, on day 1; we have:

Day\ 1 = \frac{1}{4}x

After day 1, there are:\frac{3}{4}x left ----------------- i.e x - 1/4x

On day 2, we have:

Day\ 2 = \frac{1}{3} * \frac{3}{4}x

Day\ 2 = \frac{1}{4}x

At this point, we have:

Day\ 1 = \frac{1}{4}x

Day\ 2 = \frac{1}{4}x

Left = 80 ---- pages left

The summation of all must equal x, the book pages

Day\ 1 + Day\ 2 + Left = Total\\

\frac{1}{4}x + \frac{1}{4}x+ 80= x

Simplify the left-hand side

\frac{1}{2}x+ 80= x

Collect like terms

x - \frac{1}{2}x= 80

Simplify

\frac{2-1}{2}x= 80

\frac{1}{2}x= 80

Multiply by 2

2 * \frac{1}{2}x= 80*2

x = 160

4 0
3 years ago
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