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Fynjy0 [20]
3 years ago
10

What are some programs that you have used that have condition-controlled loops and count-controlled loops?

Computers and Technology
1 answer:
gladu [14]3 years ago
8 0

Some programs that we have used that have condition-controlled loops and count-controlled loops due to the following reasons.

Explanation:

Condition-controlled loops

A program could be made more intelligent by programming it to avoid hazards. For example, if the robot vehicle is 3 cm from the edge of the table and you tell it to move forwards 5 cm, it will drive off the edge of the table. To stop this from happening, you might write a condition-controlled loop like this:

move forward

repeat until (touching table edge)  

Condition-controlled loops can be used to add a high degree of intelligence to a computer system.

Count Controlled Loops

A count controlled loop is a repetition  structure that iterates a specific number of  times

You can write a count controlled loop using a

while() loop.

For example:

counter = 0

while counter < 5:

print (“This will print 5

times”)

counter += 1

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Scilla [17]

Two different Operating Systems are

Windows 7

LINUX

Explanation:

  • Windows is an Operating System which was released by Microsoft to be used on Personal Computers.
  • They are used to manage software and perform various tasks.
  • LINUX is another type of operating system that is used on Super computers
  • Linux has been used in homes and organisation desktops in a great number.
  • It is used for great number of computing embedded tasks.
6 0
3 years ago
Fill in the blanks to make the factorial function return the factorial of n. Then, print the first 10 factorials (from 0 to 9) w
nadezda [96]

Answer:

Following are code of factorial in python language

def factorial(n): # function

   result=1 #variable

   for x in range(2,n+1): #iterating the loop

       result=result*x  #storing result

   return result #return result

for n in range(10): #iterating loop

   print(n,factorial(n)) #print factorial

Output:

Following are the attachment of output

Explanation:

Missing information :

In the question the information is missing the code is missing which we have to correct it following are the code that are mention below.

def factorial(n): # function

   result=1 #variable

   for x in range(       ): #iterating the loop

       result=  #storing result

   return  #return result

for n in range(  ): #iterating loop

   print(n,factorial(n)) #print factorial

Following are the description of code

  • We have create a function factorial  in this we have pass the one parameter i.e "n".
  • In the for loop we have pass 2,n+1 which has been used to iterating the loop calculating factorial and string the result in the result variable
  • In the main function we have pass the range on which we have to calculated the factorial
  • Finally the print function will print the factorial .

Following are the attachment snip of code in the python language

3 0
3 years ago
Evaluate if the following function is a good candidate to be placed in a library. Why or why not?
Anastaziya [24]

Answer:

No, this would not be a good candidate because it can't be used in creating new programs.

Explanation:

^

8 0
3 years ago
Read 2 more answers
Elizabeth works for a local restaurant at the end of her shift she read she’s required to write in the time that she arrived in
gavmur [86]
B - because you should always be honest when it comes to working your hours and getting paid the right amount.
5 0
3 years ago
The L-exclusion problem is a variant of the starvation-free mutual exclusion problem. We make two changes: as many as L threads
vladimir2022 [97]

Answer:

The solution is as follows.

class LFilters implements Lock {

int[] lvl;

int[] vic;

public LFilters(int n, int l) {

lvl = new int[max(n-l+1,0)];

vic = new int[max(n-l+1,0)];

for (int i = 0; i < n-l+1; i++) {

lvl[i] = 0;

}

}

public void lock() {

int me = ThreadID.get();

for (int i = 1; i < n-l+1; i++) { // attempt level i

lvl[me] = i;

vic[i] = me;

// rotate while conflicts exist

int above = l+1;

while (above > l && vic[i] == me) {

above = 0;

for (int k = 0; k < n; k++) {

if (lvl[k] >= i) above++;

}

}

}

}

public void unlock() {

int me = ThreadID.get();

lvl[me] = 0;

}

}

Explanation:

The code is presented above in which the a class is formed which has two variables, lvl and vic. It performs the operation of lock as indicated above.

6 0
3 years ago
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