How does reproductive isolation result in speciation
1 answer:
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Answer:
i) Genotype of Parent 1= TTpp
Genotype of Parent 2= ttPP
ii) The genotypes of their gametes
Parent 1= Tp
Parent 2= tP
iii) F1 generation = All TtPp (tall and purple flower)
iv) F2 phenotype ratio= 9 tall, purple: 3 tall, white: 3 dwarf, purple : 1 dwarf, white.
F2 Genotype ratio= 1:2:1:2:4:2:1:2:1
Explanation:
Let's assume that allele "T" gives tall plants while allele "t" imparts dwarfism. Likewise, the dominant allele "P" is responsible for purple flowers while recessive allele "p" gives white flowers.
i) Genotype of Parent 1—Tall plant with white flowers (pure breeding)= TTpp
Genotype of Parent 2—Dwarf plant with purple flowers (pure breeding)= ttPP
ii) The genotypes of their gametes
Parent 1= Tp
Parent 2= tP
iii) F1 generation = All TtPp (tall and purple flower)
iv) Each of the F1 plant with TtPp genotype will form four types of gametes= TP, Tp, tP and tP
A cross between TtPp x TtPp gives F2 progeny in following ratio=
F2 generation phenotype ratio= 9 tall, purple: 3 tall, white: 3 dwarf, purple : 1 dwarf, white.
Genotype ratio= 1:2:1:2:4:2:1:2:1
