Question

PLEASE HELP ASAP!

Answer 1

Answer:

7

Step-by-step explanation:

This function can never equal 0. Why? well here:

(f/g)(x) also just means $\frac{f(x)}{g(x)}$. In this case, we get $\frac{x^2-x-12}{x-4}$ Or $\frac{(x+3)(x-4)}{x-4}$. It seems like you can cancel out x-4 and bam, you get x+3 and any value should work.

However, x can never equal 4 because 4 leads to a case where you divide by 0. This is called discontinuity. Thus, the value you can't get is x=4, or 7 because when you plug 4 in, you get 0/0. Otherwise, any other real value is defined by x+3.