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Sunny_sXe [5.5K]
2 years ago
6

PLEASE HELP ASAP!

Mathematics
1 answer:
Maslowich2 years ago
5 0

Answer:

7

Step-by-step explanation:

This function can never equal 0. Why? well here:

(f/g)(x) also just means \frac{f(x)}{g(x)}. In this case, we get \frac{x^2-x-12}{x-4} Or \frac{(x+3)(x-4)}{x-4}. It seems like you can cancel out x-4 and bam, you get x+3 and any value should work.

However, x can never equal 4 because 4 leads to a case where you divide by 0. This is called discontinuity. Thus, the value you can't get is x=4, or 7 because when you plug 4 in, you get 0/0. Otherwise, any other real value is defined by x+3.

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