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nalin [4]
2 years ago
13

Answer for number 40. pleaseeeeee

Mathematics
1 answer:
Mrac [35]2 years ago
8 0

Answer:

-10, -2, 5

Step-by-step explanation:

First, you can start by making a table.

<u>Negative    |    Positive</u>

-10              |    5

-2                |

The positive number is obviously the greatest, so now we look at the negative numbers. If the numbers were on a number line, -10 would be more to the left than -2, so it's the least. That leaves -2, which is greater than -10 but less than 5.

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When the polynomial is written in standard form, what are the values of the leading coefficient and the constant? 5x + 2 - 3x^2
earnstyle [38]
Leading coefficient = -3
Constant = 2

When you order them in standard form, you need to put them in ascending order of the exponents. Therefore the -3x^2 would come first, which makes the number attached (-3) the lead coefficient. 

Also, since the number (2) without an x attached would be last (due to the power of x technically being 0), than that is the constant. 
7 0
3 years ago
I NEED HELP ASAP!!
zzz [600]

Answer:

C. {-5,-4, -3, 1, 2, 5}

Step by step explanation:

We have been given a graph and we are asked to find the domain of the relation represented in graph.

We can see that our graph is a series of unconnected points. Our function represents integer values. So we can see that our graph represents a discrete function.    

Since we know that domain of a discrete function is set of inputs values consisting of only certain values in an interval. .

The set of first value from each of the given points would made domain of our function. Upon looking at our graph we can see that domain of our function is -5,-4, -3, 1, 2 and 5.  

Therefore, option C is the correct choice.


7 0
3 years ago
Helpppp pleaseeeee✋​
Mazyrski [523]

Answer:

5 x 3 = 15 / 4 x 8 = 32 / 6 x 1.5 = 9

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
For y = 6x + (-2) what is y when x = -1
PilotLPTM [1.2K]

Answer:

12

Step-by-step explanation:

6(-1)+(-2)

-6(-2)

12

I might be wrong so please forgive me if I am.

6 0
3 years ago
Students were selected at random in a local high school to see if there was an association between gender and
Assoli18 [71]
<h3>Answer:  53%</h3>

===========================================================

Explanation:

The question asks "What percent of females participate in extracurricular activities?" This means we only focus on the second column. There are 36 women, and of this total, 19 are in extracurricular activities.

Dividing the two values leads to approximately 19/36 = 0.52777 which rounds to 0.53

Then we move the decimal to the right two spots to get 53%

Roughly 53% of the female students participate in extracurricular activities.

5 0
3 years ago
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