1) distance formula; d = √(x2-x1)² +(y2-y1)² . d= √(-4-8)² +(-3-7)² = > d= 2√61

diameter = 2*radius => 2√61 =2r => r =√61 => r² =61

midpoint of the diameter is:

Xm= -4-8 /2 -6 => -6
Ym = -1-9 /2 -5 => -5 center of the cirlce is at (-6,-5)

general equation of a circle: (x-x1)² +(y-y1)² =r² with (x1,y1) being the center of the circle.

equation: (x+6)+(y+5)=61

6 0

3 years ago

One of the tables shows a proportional relationship.

beks73 [17]

Answer:

See attached

Step-by-step explanation:

The graph of a proportional linear relationship is a line that passes through the origin (0, 0).

From inspection of the given tables, the linear equations for each table of points is:

Table 1: y = x + 1
Table 2: y = x/2
Table 3: y = x + 2
Table 4: y = 2x + 1

The only equation for which y = 0 when x = 0 is y = x/2 → Table 2.

Given points from Table 2:

(2, 1)
(4, 2)
(6, 3)
(8, 4)

To graph the line, plot the given points and draw a line through them (see attached).

5 0

2 years ago

How to find the inter quartile range of these 1,1,1,2,2,3,3,4,5

Anna007 [38]

Answer:

2.5

Step-by-step explanation:

1st Quartile (Q1): 1

2nd Quartile (Q2): 2

3rd Quartile (Q3): 3.5

IQR = Q3 - Q1 = 3.5 - 1 = 2.5

5 0

3 years ago