Sqare √113
113
10^2=100, so √100=10
11^2=121 so √121=11
√100<√113<√121
so therfor
10<√113<11
it is between 10 and 11
Answer:
y = (10/7)x
Step-by-step explanation:
Ok so this is a hard question but I believe the answer is y = (10/7)x
Answer: 20.5
Step-by-step explanation:
The last one x^4.
A: If you bring 2^-5 to the numerator which is what the - expects you to do, then you get x^5 which is 32
B: No problem here. 32 = 32
C: 2^1 * 2^4 = 2^(1 + 4) = 2^5.
C: 2^5 is 32
D: 2^4 = 16.
Answer: D does not agree with the others.
This is a 3-4-5 triangle.
Remember,
SOH-CAH-TOA
S(ine) = O(pposite)/H(ypotenuse)
C(osine) = A(djacent)/H(ypotenuse)
T(angent) = O(pposite)/A(djacent)
In Cosine, the adjacent = 3, and the Hypotenuse = 5
Hypotenuse is the longest side.
3,4,5 is the triangle that fits inside, therefore, the Opposite is 4, and Adjacent is 3
T(angent) = O(pposite)/A(djacent)
Plug in the numbers
T = 4/3
tan = 4/3 is your answer
hope this helps