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ludmilkaskok [199]
4 years ago
12

Eroa Industries bought a laser printer for $3400. It is expected to depreciate at a rate of 12% per year. What will the value of

the printer be in three years? Round to the nearest dollar.
Mathematics
1 answer:
stepan [7]4 years ago
5 0

Answer:

The laser printer will have depreciated to $1487.5

Step-by-step explanation:

The cost price is $3400 and at a depreciation rate of 12% annually

then if it is used for 3 years, it would have depreciated

(3400 × 12 × 3)/100

= 34 × 12× 3

= $1912.5

Therefore the new price value will be

$3400 - $1912.5 = $1487.5

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70% of a number is 63
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90

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7 0
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3. Study the numerical expression 7 x (9-3). Which one of the following expressions is equivalent to this numerical expression?
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First step is to do whatever is in the parentheses: 9-3.

Then you will multiply 7 by that number; which will give you the answer.

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7 0
3 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
Serga [27]

Answer:

Price of advance ticket: 15$

Price of same-day ticket: $40

Step-by-step explanation:

Let y be the price of one advance ticket and x the cost of one same day ticket.  

We know that the combined cost of one advance ticket and one same-day ticket is $55, so

y+x=55 equation (1)

We also know that 20 advance tickets and 35 same-day tickets cost $1700, so

20y+35x=1700 equation (2)

Now, let's solve our system of equations step-by-step:

step 1. Solve for x in equation (1)

y+x=55

x=55-y equation (3)

step 2. Replace equation (3) in equation (2)

20y+35x=1700

20y+35(55-y)=1700

20y+1925-35y=1700

-15y=-225

y=\frac{-255}{-15}

y=15 equation (4)

step 3. Replace equation (4) in equation (3)

x=55-y

x=55-15

x=40

We can conclude that the price of one advance ticket is $15 and the price of one same-day ticket is $40.

7 0
3 years ago
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