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baherus [9]
2 years ago
9

Please help with number 3

Mathematics
2 answers:
Pavlova-9 [17]2 years ago
7 0
6 x 3 x 4 = 72 i believe

bonufazy [111]2 years ago
7 0
Ok so 6x3x4=72 i think hope i can help you
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Hi. What is the smallest number that can be written in 6 ways as the sum of the squares of 3 primes? Also, please list them as w
Fed [463]

2019 is the smallest number.

Here are the ways:

7^2+11^2+43^2

7^2+17^2+41^2

13^2+13^2+41^2

11^2+23^2+37^2

17^2+19^2+37^2

23^2+23^2+31^2



3 0
3 years ago
What is a denominator and numerator
docker41 [41]
The numerator is the top number of a fraction and the denominator is the bottom number of a fraction
6 0
3 years ago
Read 2 more answers
Help with this please, picture above ^
Irina18 [472]

Answer:

y = -3x -2

Step-by-step explanation:

parallel lines have same slope

line d: slope (m) = -3

y intercept (b) = -2

equation y = mx + b      y = -3x -2

8 0
3 years ago
A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11
mixer [17]
Let A(t) denote the amount of salt in the tank at time t. We're given that the tank initially holds A(0)=100 lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}
\implies A'(t)+\dfrac{11}{200+33t}A(t)=484

Find the integrating factor:

\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}

Distribute \mu(t) along both sides of the ODE:

(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}
\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}
A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt
A(t)=22(200+33t)^{2/3}+C

Since A(0)=100, we get

100=22(200)^{2/3}+C\implies C\approx-652.39

so that the particular solution for A(t) is

A(t)=22(200+33t)^{2/3}-652.39

The tank becomes full when the volume of solution in the tank at time t is the same as the total volume of the tank:

200+(44-11)t=500\implies 33t=300\implies t\approx9.09

at which point the amount of salt in the solution would be

A(9.09)\approx733.47\text{ lb}
4 0
3 years ago
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