If the ratio of a model train to a real train exists 1:3 and the real train exists 12 feet then the model train exists 3 feet long.
<h3>How to estimate the ratio of the model train?</h3>
Given that the model train contains a scale of 1: 3 and the real train exists 12 feet tall.
The ratio indicates how many times one number has another number.
A ratio exists as the relationship in quantity between two things.
It conveys the quantity of one thing in words of another.
The ratio of a model train to a real train exists at 1 inch :3 inches.
Height of model train = 12 
1/4
Height of model train = 3 inches
Therefore, the ratio of a model train to a real train exists 1: 3 and if the real train exists 12 feet then the model train exists 3 feet long.
To learn more about ratios refer to:
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A. 27 is a term so therefore the answer is A
Answer: $12.32
Work: 22 x 0.44=9.68
22-9.68=12.32
Answer:
i think it is A
Step-by-step explanation:
sorry if i am wrong...hope this helped, also can i have brainliest pls?
Best to factor 5 out of the first 2 terms:
5x^2-7x+2=0 => <span>5(x^2 - [7/5]x) +2=0
Take half of [-7/5]: That'd be -7/10.
Square 7/10, add it to </span>5(x^2 - [7/5]x) +2=0 and then subtract it:
5(x^2 - [7/5]x)+ 49/100 - 49/100 ) +2=0
Then we have 5(x- [7/10] )^2 - 49/100 ) + 200/100 = 0
5(x-7/5)^2 - 245/100 + 200/100 = 0
5(x-7/5)^2 - 45/100 = 0
Dividing all terms by 5, x-7/5 = plus or minus sqrt( 9/100 )
x-7/5 = plus or minus 3/10
Then one root is x = 7/5 + 3/10, or x= 17/10 (answer #1)
The other is x = 7/5 - 3/10, or x = 14/10 - 3/10, or x = 7/10 (answer #2)
