Answer:
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Step-by-step explanation:
f(x) = sin (tan^-1 (ln(x)))
u substitution
d/du (sin u) * du /dx
cos (u) * du/dx
Let u =(tan^-1 (ln(x))) du/dx =d/dx (tan^-1 (ln(x)))
v substitution
Let v = ln x dv/dx = 1/x
d/dv (tan ^-1 v) dv/dx
1/( v^2+1) * dv/dx
=1/(ln^2x +1) * 1/x
Substituting this back in for du/dx
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
From the attached graphic, Half-life = ln (.5) / k
Half-life =.693147 / <span>0.1142
= </span><span><span><span>6.0695884413
</span>
days
The value of "k" should be negative and should have units associated with it.
</span>
</span>
We'll use the Pythagorean Theorem
130^2 = side^2 +50^2
side ^ 2 = 16,900 -2,500
side ^ 2 = 14,400
side = square root (14,400)
side = 120 feet
I’m going to say B I could be wrong
No. 0.54 is equal to 0.540
0.540 > 0.529