All categories

2 years ago

Share £180 in the 4:5

Mathematics

1 answer:

marissa [1.9K]2 years ago

4 0

4 + 5 = 9
£180 / 9 = £20

£20 x 4 = £80
£20 x 5 =£100

Answer:
£80 : £100

hope it helped :)

You might be interested in

0.05% as a fraction in simplest form

fiasKO [112]

0.05=5/100
5/100=1/20

3 0

2 years ago

If 141 people attend a concert and tickets for adults cost $3.5 while tickets for children cost $2.5 and total receipts for the

Arturiano [62]

Answer: There are 69 adults and 72 children went to the concert.

Step-by-step explanation:

Let x be the number of adults, and y be the number of children.

x + y = 141

3.5x + 2.5y = 421.5

x + y =141

x = 141 - y

3.5(141 - y) + 2.5y = 421.5

493.5 - 3.5y + 2.5y = 421.5

493.5 - y = 421.5

-y = -72

y = 72

x + y = 141

x + 72 = 141

x = 69

6 0

3 years ago

Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

Pepsi [2]

Answer:

Option 3 - $y=-6x+28$

Step-by-step explanation:

Given : Perpendicular to the line $x - 6y = 8$ ; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation $x - 6y = 8$

Converting into slope form $y=mx+c$ ,

Where m is the slope.

$y=\frac{x-8}{6}$

$y=\frac{x}{6}-\frac{8}{6}$

The slope of the equation is $m=\frac{1}{6}$

The slope of the perpendicular equation is $m_1=-\frac{1}{m}$

The required slope is $m_1=-\frac{1}{\frac{1}{6}}$

$m_1=-6$

The required equation is $y=-6x+c$

Substitute point (x,y)=(4,4)

$4=-6(4)+c$

$4=-24+c$

$c=28$

Substitute back in equation,

$y=-6x+28$

Therefore, The required equation for the line is $y=-6x+28$

So, Option 3 is correct.

8 0

2 years ago

PLEASE HELP MEEEE HURRRY!!! :)

sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

$\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}$

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

$\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}$ First, I swapped the first and third rows.

$\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}$ Leading coefficient of row 2 canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}$ The start value of row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}$ Matrix rows 2 and 3 were swapped.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}$ Leading coefficient in row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}$

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

$\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}$

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0

3 years ago

Write a problem to fit this equation 2K + 5 =29

Degger [83]

2K + 5 = 29

(2 x K) + 5 = 29

29 - 5 = 24

24 divided by 2 = 12 (This is K)

K = 12

(2 x 12) + 5 = 29

24 + 5 = 29

6 0

2 years ago