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3 years ago

Solve: 48y^5=27y^3 please solve:))))))))

Mathematics

2 answers:

miss Akunina [59]3 years ago

4 0

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

y=0,−3/4,3/4

N76 [4]3 years ago

3 0

48y^5=27y^3

subtract 27 y^3 from each side

48y^5-27y^3=0

factor out 3y^3

3y^3(16y^2 -9)=0

factor

3y^3 (4y-3) (4y+3) =0

using the zero product property

3y^3 =0 4y-3 =0 4y+3 =0

y^3=0 4y=3 4y = -3

y=0 y = 3/4 y = -3/4

Answer: y = -3/4, 0, 3/4

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2 years ago

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3 years ago

If exactly 180 people sign up for a charter flight, Leisure World Travel Agency charges $298/person. However, if more than 180 p

lesantik [10]

Answer:

The max. revenue is $57,121.

This happens with 239 passengers.

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Step-by-step explanation:

Let the variable "P" denote the number of passengers.

If P=180, then the ticket cost is $298/person. Then the price is reduced by $1 for each additional person.

In general, if P=(180+x), then the ticket cost becomes (298-x) per person.

The revenue can be defined as the ticket cost multplied by the number of passengers:

$R=P*T=(180+x)(298-x)=53,640-180x+298x-x^2\\\\R(x)=-x^2+118x+53,640$

We can derive R and equal to zero to maximize the function.

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$P=180+x=180+59=239$

The price of the tickets is

$T=298-59=239$

The revenue is:

$R(59)=(180+59)(298-59)=239*239\\\\R(59)=57,121$

3 0

3 years ago