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sdas [7]
3 years ago
9

Solve: 48y^5=27y^3 please solve:))))))))

Mathematics
2 answers:
miss Akunina [59]3 years ago
4 0
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

y=0,−3/4,3/4
N76 [4]3 years ago
3 0

48y^5=27y^3

subtract 27 y^3 from each side

48y^5-27y^3=0

factor out 3y^3

3y^3(16y^2 -9)=0

factor

3y^3 (4y-3) (4y+3) =0

using the zero product property

3y^3 =0  4y-3 =0  4y+3 =0

y^3=0      4y=3      4y = -3

y=0  y = 3/4    y = -3/4

Answer:   y =  -3/4, 0,  3/4

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Step-by-step explanation:

*this is <em>only </em>if you are allowed to use a calculator*

1. You have to add the total of the cats and dogs

Why? Here, let me put it this way. You have a test with two sections: math and science. If there are 2 Maths Questions and 2 Science questions, what percent of the test are math questions? You would not say 2/2 and say 100. You would say 2/4 because it is obvious. You do the same in this case but it is not as noticeable because you are dealing with bigger numbers.

15 + 12 = <u>27</u>.

2. Solve

<u>a. </u>There are 15 dogs and 12 cats that makes up 27 pets total.

So you have to do 12/27 for cats,

15/27 for dogs. The fractions equal one and It shows you how much of one is there compared to the total.

<u>b. </u><u><em>Simplify</em></u>

You can simplify these fractions:

for 12/27, divide the numerator and the denominator by 3.

You get 4/9

Divide 15/27 for dogs by 3 as well to get 5/9.

5+4 is 9, which means that I am doing the math correctly.

According to the calculator, 5/9 is 55.556, and 4/9 is 44.444

They should be accurate because there are more dogs than cats and the percentage for dogs are higher. Hence, this is correct.

Cats = 4/9 = 44.444%

Dogs = 5/9 = 55.556%

Hope this helps :)

-jp524

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