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Elodia [21]
3 years ago
8

Imagine an experiment with 20 groups, and within each group, there are 50 participants. How many degrees of freedom are there fo

r the within subjects factor?
Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer: There are 980 degrees of freedom for the within subjects factor.

Step-by-step explanation:

Since we have given that

Number of groups = 20

Number of participants in each group = 50

So, number of participants in 20 groups is given by

20\times 50\\\\=1000

As we know that

Degrees of freedom for the within subjects factor would be

v=n-k\\\\v=1000-20\\\\v=980

Hence, there are 980 degrees of freedom for the within subjects factor.

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Step-by-step explanation:

Y=1/6x+b

Plug in (-6,1)

1=1/6(-6)+b

1=-1+b

Add 1 to both sides

1+1=b

2=b

Y=1/6x+2

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
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Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

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