Answer:
2
Step-by-step explanation:
Let's solve the given system of equations.
<u>Given system</u>
x +3y= 10 ----(1)
-2x -2y= 4 ----(2)
From (2):
-2(x +y)= 4
Dividing both sides by -2:
x +y= -2 ----(2)
Thus, options 3 and 4 are incorrect as x +y≠ -2.
(1) -(2):
(x +3y) -(x +y)= 10 -(-2)
Expand:
x +3y -x -y= 10 +2
2y= 12
Divide both sides by 2:
y= 12 ÷2
y= 6
Substitute y= 6 into (2):
x +6= -2
x= -6 -2
x= -8
Options (1) and (2) differs only by the value of the expression of -x +y. Thus, let's find its value in the given system of equations.
-x +y
= -(-8) +6
= 8 +6
= 14
Thus, option 2 is the correct option.
P=1
q= 10
p=1 because 2x1 equals 2
q= 10, because 10 minus 3=7(just add 7+3)
Answer:
C
Step-by-step explanation:
We know that the value of 1 is 4,
So, there are 2 difference,
1 is 4
2 is 6
3 is 8
4 is 10
5 is 12
So, the first five terms is 4, 6 ,8 ,10, 12.
