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3 years ago

Find the length of the missing side: the lengths are 14m & 5m

Mathematics

1 answer:

rewona [7]3 years ago

5 0

Of a triangle? Then it would be 14.87 if you're looking for the hypotenuse.

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Please help immediately

Burka [1]

Answer: $f'(1)=\dfrac{4}{2y+1}$

Step-by-step explanation:

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given: 0 = 2x² - xy - y²

Derivative: 0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

y'(2y + 1) = 4x

$y'=\dfrac{4x}{2y+1}$

$\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}$

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3 years ago

Rapid Rental Car charges a $30 rental fee, $15 for gas, and $0.65 per mile driven. For the same car, Capital Cars charges $35 fo

andreev551 [17]

You gave me numbers but forgot the question. Without a question there is no answer.

5 0

3 years ago

Do you prefer Thai food or chinese food. is the question baised

Ksenya-84 [330]

No, this would not be a biased question unless the people asked were all Thai people or all Chinese people. Then the information would be skewed because naturally, Chinese people would favor Chinese food and same for Thai.

4 0

3 years ago

Read 2 more answers

PLEASE HELP What is the value of x?

AleksAgata [21]

The angles inside a triangle add up to 180°
The 3rd angle is supplementary to (6x+1)°
Supplementary means they make a straight line (i.e 180°)

1st angle = 79°
2nd angle = (2x+10)°
3rd angle = 180° - (6x+1)°

180 = 79 + (2x+10) + 180 - (6x+1)
180 = 79 + 2x + 10 + 180 - 6x - 1
combine like terms
180 - 180 - 79 - 10 + 1 = 2x - 6x
-88 = -4x
-88/-4 = x
22 = x

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago